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GuDViN [60]
3 years ago
13

The gas sample has now returned to its original state of 1.00 atm, 20.0 ∘c, and 1.00 l. what will the pressure become if the tem

perature of the gas is raised to 200.0 ∘c and the piston is not allowed to move?
Physics
1 answer:
steposvetlana [31]3 years ago
3 0

At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 473.15 x 1.00 / 293.15

<span>P2 = 1.61 atm</span>

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A 74.1 kg high jumper leaves the ground with
pishuonlain [190]

Answer:

4.80 m

Explanation:

We are given the mass of the high jumper, its initial velocity, and the acceleration of gravity. We are trying to find the vertical displacement of the high jumper.

Let's set the upwards direction to be positive and the downwards direction to be negative.

List out the relevant known variables.

  1. v₀ = 9.7 m/s
  2. a = -9.8 m/s²
  3. Δx = ?

We still need one more variable in order to use the constant acceleration equations. Since we are trying to find the max height of the jumper, we can use the fact that at the top of its trajectory, its final velocity will be 0 m/s.

    4. v = 0 m/s

Using these four variables, let's find the constant acceleration equation that contains these variables:

  • v² = v₀² + 2aΔx

Substitute the known values into the equation and solve for Δx.

  • (0)² = (9.7)² + 2(-9.8)Δx
  • 0 = 94.09 + (-19.6)Δx
  • -94.09 = -19.6Δx
  • Δx = 4.80

The high jumper can jump to a max height of 4.80 m.

7 0
2 years ago
(3) A Ninja motorcycle is moving down I95 at 160 miles per hour (72 m/s) and a cop uses a radar gun to measure the speed. Using
Virty [35]

Answer:

it does use it at doppler

Explanation:

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5 0
2 years ago
A ball starts from rest and rolls down a hill at a constant acceleration of 5 m/s2. If it travels for 8 m how fast is it going i
makkiz [27]

Hi there!

We can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = final velocity (? m/s)
vi = intial velocity (0 m/s)

a = acceleration (5 m/s²)

d = displacement (8 m)

Plug in the givens and solve.

v_f^2 = 0 + 2(5)(8)\\\\v_f = \sqrt{80} = \boxed{8.944 \frac{m}{s}}

5 0
2 years ago
H. The length of the shadow is different in evening and in the day. Justify​
Vinvika [58]

the shadows are exactly the same length in the morning as they are in the evening.

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3 0
2 years ago
Read 2 more answers
Once juno reaches jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft
Komok [63]

In very very very round figures . . .

-- Jupiter is about 5.2 times as far from the sun as the earth is.

-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about

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Time = (distance) / (speed)

The speed of light and radio is 300,000 km/second

Time = (630 million / 300 thousand)

<em>Time = 2,100 seconds</em>

That's 35 minutes.

4 0
3 years ago
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