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kicyunya [14]
3 years ago
15

Can there be two places on the surface of the Earth having the same local time but opposite seasons? A. No, there cannot be two

such places. B. Yes, only if both of them are on the equator. C. Yes, only if both are in the different hemispheres. D. Yes, only if both of them are at the opposite poles.
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer : Yes, only if both are in the different hemispheres.

Explanation : At the same local time, the southern hemisphere points away from the sun then creating the winter during June, July and August and when the south pole is tilted toward the sun and the northern hemisphere is tilted away then creating summer in the southern hemisphere is in December , January and February.

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Which of the following lists are all renewable resources?
earnstyle [38]

The answer is A.

Hydroelectric, which is usually generating electricity through use of a dam.

Solar, energy from the Sun.

Biomass, organic material formed from plant matter.

3 0
3 years ago
Can you answer this math homework? Please!
kap26 [50]

\large \mathfrak{Solution : }

9. An object which is in circular motion (moving along a circle) is said to be accelerating because it changes it's direction constantly even if it is moving with a constant speed. cuz acceleration is change in either magnitude or direction of an object with respect to time.

therefore, it's still acceleration as change in direction with time.

10. Average speed of an object can be calculated by dividing the total distance covered by an object by time taken to cover that distance.

i.e

  • \boxed{speed =  \dfrac{distance}{time} }

it can be re- arranged to find the distance as :

  • \boxed{distance = speed \times time}

  • time =  \dfrac{distance}{speed}

11. speed = 20 m/s : conversion into km/h

distance covered : 4 km = 4000 m

  • time =  \dfrac{distance}{speed}

  • t =  \dfrac{4000}{20}

  • t =  200 \:  \: sec

time taken = 200 seconds

12. let's use the first equation of motion to find the acceleration :

  • v = u + at

  • 50 = 80 + 120a

  • 50 - 80 = 120a

  • a =  \dfrac{ - 30}{120}

  • a = -   \dfrac{1}{4} m/s {}^{2}

  • - 0.25 \:  \: m/s {}^{2}
3 0
3 years ago
An eccentric inventor attempts to levitate a cork ball by wrapping it with foil and placing a large negative charge on the ball
djverab [1.8K]

Answer:

because of the idea that like charges get repulsion as a force.

Explanation:

because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.

7 0
3 years ago
What are the elements of NaCl
Lana71 [14]

The elements in NaCl are Na -sodium and Cl - chlorine

<u>Explanation:</u>

  • sodium chloride (NaCl) is also known as common salt. The molar ratio of NaCl is 1:1 and has the molar mass of 22.99 and 35.45 respectively. The molar mass of NaCl is 58.443 g/mol. It is a odorless and colourless cubic crystal.
  • It has the melting point of 800.7°C and has the boiling point of 1465°C. It has a face centered cubic crystal structure.The elements in NaCl are Na -sodium and Cl - chlorine

                                                        2Na+Cl_{2} → 2NaCl

4 0
3 years ago
Calculate the energy of a photon having a wavelength in thefollowing ranges.(a) microwave, with λ = 50.00 cmeV(b) visible, with
IgorLugansk [536]

(a) 2.5\cdot 10^{-6}eV

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

For the microwave photon,

\lambda=50.00 cm = 0.50 m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{0.50 m}=4.0\cdot 10^{-25} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-25}J}{1.6\cdot 10^{-19} J/eV}=2.5\cdot 10^{-6}eV

(b) 2.5 eV

For the energy of the photon, we can use the same formula:

E=\frac{hc}{\lambda}

For the visible light photon,

\lambda=500 nm = 5 \cdot 10^{-7}m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-7} m}=4.0\cdot 10^{-19} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.5 eV

(c) 2500 eV

For the energy of the photon, we can use the same formula:

E=\frac{hc}{\lambda}

For the x-ray photon,

\lambda=0.5 nm = 5 \cdot 10^{-10}m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-10} m}=4.0\cdot 10^{-16} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-16}J}{1.6\cdot 10^{-19} J/eV}=2500 eV

6 0
3 years ago
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