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kicyunya [14]
3 years ago
15

Can there be two places on the surface of the Earth having the same local time but opposite seasons? A. No, there cannot be two

such places. B. Yes, only if both of them are on the equator. C. Yes, only if both are in the different hemispheres. D. Yes, only if both of them are at the opposite poles.
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer : Yes, only if both are in the different hemispheres.

Explanation : At the same local time, the southern hemisphere points away from the sun then creating the winter during June, July and August and when the south pole is tilted toward the sun and the northern hemisphere is tilted away then creating summer in the southern hemisphere is in December , January and February.

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A car traveling at 21 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration? Ans
allsm [11]
-3.5mls squared = a

0mls = 21mls + a(6s)
-21mls/6s

The equation used in this is vf = vi + at

Hope this helps!
4 0
3 years ago
Choose the correct statement regarding projectile motion in the absence of air resistance. Assume the object is at sea level mov
pishuonlain [190]

Answer:

Explanation:

The magnitude of the acceleration in the x direction is always zero: TRUE.

At the apex, in the y direction the velocity is zero and the accelration is positive. TRUE.

At the apex, in the x direction, the velocity is zero and the acceleration is zero. FALSE. The accelration is zero, but the velocity is the same it had when it was shot.

The magnitude of the velocity in the y direction is always constant. FALSE, it's subject to gravity and it's velocity varies as v=v_0 - 9.81ms^{-2} t

At the apex, in the Y direction, the velocity is negative and the acceleration is zero. FALSE. Velocity is zero, Acceleration is 9.81 ms^{-2}, towards the negative y axis

7 0
3 years ago
A triangle has two sides of length 10 cm and 14 cm. what can you say about the length of the third side?
Anton [14]

A side of any triangle is less than the sum of the other two sides so the third side must be less than 24cm.

<h3>What is a triangle?</h3>

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle, some of which may be the same.

The sum of all three angles inside a triangle will be 180° and the area of a triangle is given as (1/2) × base × height.

There are many types of triangles such that right-angle triangles, equilateral triangles, and much more.

In any triangle, the sum of two sides is always greater than the third side.

If the third side is equal to the sum of two sides then it will be a straight line rather than a triangle.

It means 10 + 14 > third side

24 cm > third side

Hence "A side of any triangle is less than the sum of the other two sides so the third side must be less than 24cm".

For more about triangles,

brainly.com/question/2773823

#SPJ4

3 0
1 year ago
What uniform magnetic field, applied perpendicular to a beam
schepotkina [342]

Answer:

The magnetic field is 2.11\times10^{-5}\ T

Explanation:

Given that,

Speed v=1.30\times10^{6}\ m/s

Radius = 0.350 m

We need to calculate the magnetic field

Using formula of magnetic field

B =\dfrac{mv}{qr}

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

B=\dfrac{9.1\times10^{-31}\times1.30\times10^{6}}{1.6\times10^{-19}\times0.350}

B=2.11\times10^{-5}\ T

Hence, The magnetic field is 2.11\times10^{-5}\ T

5 0
4 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl
aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i:  unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R=  131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2}  }

D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2}  }

D₂= 167.21 cm

Direction of the second displacement

\beta = tan^{-1} \frac{D_{y}}{D_{x} }

\beta = tan^{-1} \frac{62.18}{155.22 }

β= 21.8°

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0
4 years ago
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