Answer:
ar = 5.86*10^-3 m/s^2
Explanation:
In order to calculate the radial acceleration of the Earth, you first take into account the linear speed of the Earth in its orbit.
You use the following formula:
(1)
G: Cavendish's constant = 6.67*10^-11 m^3 kg^-1 s^-2
Ms: Sun's mass = 1.98*10^30 kg
r: distance between Sun ad Earth = 1.50*10^8 km = 1.50*10^11 m
Furthermore, you take into account that the radial acceleration is given by:
(2)
You replace the equation (1) into the equation (2) and replace the values of all parameters:
The radial acceleration of the Earth, towards the sun is 5.86*10^-3 m/s^2
Answer:
The potential energy has a maximum when the ball is a time that is half of the time for total travel
Explanation:
Generally potential energy is a the varies directly with the height according to this formula
and the ball attains a maximum height when the time is equal to half of the total time taken to travel
Explanation:
The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.
The car has slowed down because of the deceleration or decelerating force acting on it. The decelerating force acting on it is generated by the application of brakes or the frictional force acting in the opposite direction of car's motion.
Any lump of osmium is. Iridium and gold are also very close.
