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3 years ago

7

What is the most dense thing in the world

2 answers:

Mashcka [7]3 years ago

7 0

Any lump of osmium is. Iridium and gold are also very close.

Bogdan [553]3 years ago

6 0

Since you said "thing," the densest naturally-occurring element would be osmium.

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The mass of the boy is 35 kilograms. What is the force of friction that slowed him down?

pychu [463]

Answer:

Newton's F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

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3 years ago

When an explanation to a problem is accepted as always true, it is

Vaselesa [24]

I believe the best answer is law, as scientific laws are accepted to be true under the proper conditions.

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3 years ago

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El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es

Bess [88]

Answer:

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

Explanation:

Asumiendo que la presión ( $P$ ), medida en pascales, tiene una distribución uniforme sobre la superficie del pistón, se calcula a partir de la siguiente expresion:

$P = \frac{F}{A}$

Donde:

$F$ - Fuerza motriz, medida en newtons.

$A$ - Área del pistón, medida en metros cuadrados.

La fuerza motriz es equivalente al peso del automóvil. El área del pistón ( $A$ ), medido en metros cuadrados, es determinado por:

$A=\frac{\pi}{4}\cdot D^{2}$

Donde $D$ es el diámetro del pistón, medido en metros.

Si $D = 0.32\,m$ y $F =17,640\,N$ , entonces la presión neumática es:

$A = \frac{\pi}{4}\cdot (0.32\,m)^{2}$

$A \approx 0.080\,m^{2}$

$P = \frac{17,640\,N}{0.080\,m^{2}}$

$P = 220,500\,Pa$

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

8 0

3 years ago

What is the role of electrical forces in nuclear fission

77julia77 [94]

The electrical forces pulls nucleus apart

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3 years ago

The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t

Bumek [7]

Answer:443.1 s

Explanation:

Given

Engine of a locomotive exerts a force of $8.1\times 10^5 N$

Mass of train $=1.9\times 10^7$

Final speed (v) $=68 km/h \approx 18.88 m/s$

F=ma

so $acceleration(a) =\frac{F}{m}=\frac{8.1\times 10^5}{1.9\times 10^7}$

$a=0.042631 m/s^2$

and acceleration is

$a=\frac{v-u}{t}$

$0.042631=\frac{18.88-0}{t}$

$t=443.089 \approx 443.1 s$

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3 years ago

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