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Romashka [77]
4 years ago
15

If an environment changes what must a spices do to survive

Physics
1 answer:
zhenek [66]4 years ago
6 0
This is easy, the spices must adapt to their new environment to survive
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When an object speeds up, it has ___________ acceleration.
Fittoniya [83]

Explanation:

when an object speeds up,it has positive acceleration.

hope it helps....

5 0
3 years ago
At 1.70 atm, a sample of gas takes up 4.25L. If the pressure in the gas is increased to 2.40 atm, what will the new volume be?
ozzi

Answer:

This question is an example of Boyle's gas law which states that the pressure of a given mass of a gas is inversely proportional to its volume at a constant temperature. The formula for this gas law is:

P1·V1 = P2·V2

P1 = initial pressure = 1.7 atm

V1 = initial volume = 4.25 L

P2 = final pressure = 2.4 atm

V2 = final volume = ?

Rearrange the formula to isolate V2. Substitute the known data and solve.

V2 = P1·V1/P2

V2 = 1.7 atm·4.25 L/2.4 atm = 3.0 L to two significant figures

The new volume will be ~3.0 L.

Explanation:

3 0
4 years ago
How do astronomers use rocks from the moon to estimate the age of the solar system?
Firlakuza [10]

Answer:

Might be better to use geophysicists to date the moon rock via   Radioactive Age-Dating  Carbon 12

Explanation:

6 0
3 years ago
Q2. A certain machine is used to lift a load of 500N when an effort of 50N is applied to the machine the load is raised by 10m a
Natalija [7]

Answer:

2%

Explanation:

E=l/E x r/R x100%

=5000/50 x 0.1/0.6 x100

=2% or 166.7

8 0
2 years ago
Read 2 more answers
A 2-kg rock is thrown vertically upward at a speed of 3.2 m/s from the surface of the moon. If it returns to its starting point
worty [1.4K]

Answer:

1.6 m/s2

Explanation:

Let g_m be the gravitational acceleration of the moon. We know that due to the law of energy conservation, kinetic energy (and speed) of the rock when being thrown upwards from the surface and when it returns to the surface is the same. Given that g_m stays constant, we can conclude that the time it takes to reach its highest point, aka 0 velocity, is the same as the time it takes to fall down from that point to the surface, which is half of the total time, or 4 / 2 = 2 seconds.

So essentially it takes 2s to decelerate from 3.2 m/s to 0. We can use this information to calculate g_m

g_m = \frac{\Delta v}{\Delta t} = \frac{0 - 3.2}{2} = \frac{-3.2}{2} = -1.6 m/s^2

So the gravitational acceleration on the Moon is 1.6 m/s2

8 0
3 years ago
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