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Diano4ka-milaya [45]
4 years ago
5

________________ is a synthetic polymer classified as plastics.

Chemistry
2 answers:
Igoryamba4 years ago
8 0

Answer: Polythene

Polythene is a synthetic polymer classified as plastics.

Explanation:

Polythene is formed artificially from several repeating units of ethene molecules (monomers) in a reaction known as polymerization.

The polyethene can be represented as [CH2-CH2]n, where n is thousands to ten thousands unit of ethene.

It is used to make

- plastic bags,

- cable insulators

- plastic crates etc

Thus, polythene is a synthetic polymer of ethene, and classified as plastics.

Pavlova-9 [17]4 years ago
6 0

Answer:

Polyethylene

Explanation:

They are man made polymers consisting of several long chain monomers of the same chemical composition. It has a chemical formula of (C2H4)n where n is the number of units or chain.

It is the most popular synthetic polymer due to its easy, simple structure and lightweight compared to other synthetic polymers produced commercially.

It is used in making grocery bags, automobile parts etc.

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In the chemical reaction below, what Is the product? C+o2 -> Co2
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Explanation:

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3 years ago
Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a particular experiment, the concentrations
bearhunter [10]

The question is incomplete, here is the complete question:

Consider the following chemical reaction: H₂ (g) + I₂ (g) ⇔ 2HI (g) At equilibrium in a particular experiment, the concentrations of H₂, I₂, and HI were 0.15 M, 0.033 M and 0.55 M respectively. The value of Keq for this reaction is

<u>Answer:</u> The value of K_{eq} for the given reaction is 61.11

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_[eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is written as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[HI]^2}{[H_2][I_2]}

We are given:

[HI]_{eq}=0.55M

[H_2]_{eq}=0.15M

[I_2]_{eq}=0.033M

Putting values in above expression, we get:

K_{eq}=\frac{(0.55)^2}{0.15\times 0.033}\\\\K_{eq}=61.11

Hence, the value of K_{eq} for the given reaction is 61.11

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When water is decomposed into hydrogen and oxygen, these gases cannot combine again to reform water?
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