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fiasKO [112]
3 years ago
14

The admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day, 2200 people enter the fair and $

5050 is collected. How many children and how many adults attended?
Mathematics
1 answer:
love history [14]3 years ago
7 0
$1.50C + $4A= $5050
 C + A = 2200

-4(C + A = 2200)
-4C - 4A = -8800
1.50C+4A = 5050
-----------------------
-2.5C =- 3750
-2.5C/-2.5 =- 3750/-2.5
C = 1500

C + A = 2200
1500 + A =2200
1500 - 1500 + A = 2200 - 1500
A = 700

CHECK
$1.50C + $4A= $5050
$1.50(1500) + $4(700)= $5050
$2250 +$2800 =$5050
$5050 = $5050

 C + A = 2200
1500 + 700 =2200
2200 = 2200
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Can someone please help me with question 35?
Genrish500 [490]
First you would find the area of the triangle which would be 84×92 then divide that answer by 2.
Then you will find the area of the circle using the given radius 20.5.
Lets work it out.
84×92=7728
7728÷2=3864 ft²
3864 ft² is the area of the backyard including the pool.
A=pi(20.5)²
A=1320.25 ft²
1320.25 ft² is the area of the pool.
Now we have to subtract to get the area of the backyard without the pool.
3864-1320.25=2543.75 ft²
2543.75 ft² is your answer.
Hope This Helps and God Bless!
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konstantin123 [22]

For the equation  F(x) = ax² + bx + c we have:

  • maximum value if a<0
  • minimum value if a>0

F(x) = -3x² + 18x + 3    ⇒  a = -3, b = 18

a < 0    ⇒   the function has a maximum value

Quadratic function has the maximum value (or minimum) at vertex of its parabola.

The maximum value is k at x=h where:  h=\dfrac{-b}{2a}  and  k = F(h)

h=\dfrac{-18}{2\cdot(-3)}=3\\\\F(3)=-3\cdot3^2+18\cdot3+3=-27+54+3=30

Therefore:

<h3> The function has a maximum value of 30 at x = 3</h3>

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