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Tcecarenko [31]
2 years ago
10

a bicycle accelerates at 1 m/s² from an initial velocity of 4 m/s² for 10s. Find the distance moved by it during this interval o

f time?​
Physics
1 answer:
BaLLatris [955]2 years ago
6 0

Answer:

90 m

Explanation:

Acceleration, a=\frac {v-u}{t} where v and u are final and initial velocities respectively, t is the time taken

Substituting 1 m/s^{2} for a,  4 m/s for u and 10 s for t then

1*10=v-4

v=14 m/s

From kinematic equations

v^{2}=u^{2}+2as

Making s the subject then

s=\frac {v^{2}-u^{2}}{2a}=\frac {14^{2}-4^{2}}{2\times 1}=90 m

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