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3 years ago

Describe the relationship between the radius of a cation and that of the atom from which forms.

1 answer:

4 0

The radius of the cation is much smaller than the corresponding neutral atom.(b) The radius of an anion is much larger than the corresponding neutral atom.Explanation:The size of the atom or ion is inversely proportional to the nuclear charge experienced by the electrons.(a)The size of the cation is smaller than the size of the corresponding neutral atom. This is because after removal of an electron from the highest principle energy level the nuclear charge experienced by the valence electrons increases resulting in the decrease in size.(b)The size of an anion is larger than the size of the corresponding neutral atom. In an anion, an extra electron is added to the highest principle energy level but the effective nuclear charge pulling the electrons towards the nucleus is still same. The net effective nuclear charge experienced by the electrons present in the outermost shell decrease. Moreover, due to the added electron, the repulsion between the electrons also increases resulting in the increase in size

Make since? i hope this helps

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Which value would be required to estimate the lattice energy for the hypothetical ionic compound MgH2?

Sonja [21]

D, the energy of formation is equal to the dissociation. so from magnesium ions and Hydrogen ions, when they form the lattice energy is equal to formation-dissociation, as they aren't going to dissociate (fixed in lattice) the formation should be the same as the the overall lattice energy.

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3 years ago

Which phrases describe all the outer planets' motion? Check all that apply.

viktelen [127]

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3 years ago

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

4 years ago

The standard molar enthalpy of vaporization for water is 40.79kJ/mol. What mass of steam is required to release 500 kJ of energy

bezimeni [28]

Answer:

220.9g of water are required

Explanation:

The molar enthalpy of vaporization is defined as the heat released when 1 mole of water changes from liquid to gas.

For water, 1 mole releases 40.79kJ. To release 500kJ are necessaries:

500kJ * (1mol / 40.79kJ) = 12.26 moles are necessaries

To convert moles to grams we must use the molar mass (H2O = 18.02g/mol):

12.26 moles * (18.02g / 1 mol) =

<h3>220.9g of water are required</h3>

4 0

3 years ago

Is Fe2(CO3)3 soluble?

MA_775_DIABLO [31]

Yes it’s a soluble because the carbonate should dissolve in any strong acid with much effervescence

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3 years ago