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3 years ago

How are a magnets magnetic force and magnetic field different?

Chemistry

2 answers:

boyakko [2]3 years ago

5 0

They are different because there is a negative and positive charge which attracts different magnetic forced

patriot [66]3 years ago

3 0

They are different because the magnetic force is attraction or repulsion that arises between electrically charged particles because of their motion. It is the basic force responsible for such effects as the action of electric motors and the attraction of magnets for iron. magnetic item whereas the magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts.

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The hydrogen gas formed in a chemical reaction is collected over water at 30.0 ∘c at a total pressure of 734 mmhg . part a what

In-s [12.5K]

At a temperature of 30 deg C, the vapour pressure of water H2O is about 32 mm Hg. Therefore at a total pressure f 734 mm Hg, the partial pressure of the Hydrogen gas collected is:

<span>P Hydrogen = 734 mm Hg – 32 mm Hg = 702 mm Hg</span>

6 0

3 years ago

Read 2 more answers

Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty fo

jarptica [38.1K]

Answer:

a. Too close to zero

b. ΔS > 0

c. Too close to zero

d. ΔS < 0

e. ΔS > 0

Explanation:

In order to answer this question we need to compare the change in number of mol in the gas state for the products vs the reactants.

An increase in number moles gas leads to a positive change in entropy. Conversely a decrease will mean ΔS is negative.

Now we can solve the parts in this question.

a. H₂ (g) + F₂ (g) ⇒ 2 HF (g)

We have no change in the number of moles gas products minus reactants. Therefore is too close to zero to decide since there is no change in mol gas.

b. 2 SO₃ ( g) ⇒ 2 SO₂ (g) + O₂ (g)

We have three moles of gas products starting with 2 mol gas SO₂, therefore ΔS is positive.

c. CH₄ (g) + 2 O₂ (g) ⇒ CO₂ (g) + 2 H₂O (g)

Again, we have the same number of moles gas in the products and the reactants (3), and it is too close to zero to decide

d. 2 H₂S (g) + 3 O₂(g) ⇒ 2 H2O (g) + 2 SO₂ (g)

Here the change in number of moles gas is negative ( -1 ), so will expect ΔS < 0

e. 2H₂O₂ (l) ⇒ 2H₂O(l) +- O2(g)

Here we have 1 mol gas and 2 mol liquid produced from 2 mol liquid reactants, thus the change in entropy is positive.

3 0

2 years ago

Which is not a characteristic of minerals

dem82 [27]

I think d is wrong because Everything else is correct for sure. also, minerals vary in the position they hold and have different chemical compounds.

6 0

2 years ago

Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp

gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

$ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})$

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in j/mol R Ea is

Ea=35.5*1000 j/mol R

$ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492$

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}