<span>The first thing that needs to be done in order to answer the question above is to balance first the chemical equation by seeing to that the number of moles of a certain element on the reactant side is equal to the number of moles in the product side. 4NH3 + 5O2 4NO + 6H2O The mole fraction between the NH3 and NO is therefore 4:4 or 1:1.</span>
<span>
Evaporation occurred between the reaction of the hydrochloric acid and the arsenic group because there is a formation of gas. A
liquid is cooled if condensation exceeds evaporation. This is because the cooling of the liquid decreases the kinetic energy of the
molecules. Their movement is being restricted by the colder temperature. The
molecules tend to be closer with each other. Also, because of their restricted
movement, the liquid may turn into solid due the colder temperature. An example
of this is the cooling of liquid water by placing it into the refrigerator into
solid water (ice).</span>
I think the correct answer would be negative change in enthalpy, low temperature and negative entropy. Freezing of water is an exothermic process which means heat is released to the surroundings so negative enthalpy. And this is seen in the change to a lower temperature. Entropy is negative which signifies that there is more order as water freezes.
Answer:
You are moving because the Earth and everything in our solar system is constantly moving. ... As the Earth rotates, it also moves, or revolves, around the Sun. The Earth's path around the Sun is called its orbit. It takes the Earth one year, or 365 1/4 days, to completely orbit the Sun.
Answer: 1. 
moles
2. 90 mg
Explanation:
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 
moles of ozone is removed by =
moles of sodium iodide.
Thus moles of sodium iodide are needed to remove 
moles of 
2. 
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by =
moles of sodium iodide.
Mass of sodium iodide= 
(1g=1000mg)
Thus 90 mg of sodium iodide are needed to remove 13.31 mg of .
