Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
When the the concentrations of both buffer components (the weak acid and its conjugate base) are equal:
[base] = [acid]
So, pH=pKa+log1 = pKa
<u>pH is equal to pKa of weak acid of buffer system
.</u>
When buffer contains more of weak acid than conjugate base:
[base] < [acid]
log [base]/[acid] = Negative,
So,
<u>When more of acid component is present, the pH is more acidic. (It decreases)</u>
When buffer contains more of conjugate base than weak acid:
[base] > [acid]
log [base]/[acid] = Positive,
So,
<u>When more of acid component is present, the pH is more acidic. (It increases)</u>
<span>Isopentane, Câ‚…Hâ‚â‚‚, also called methylbutane or 2-methylbutane, is a branched-chain alkane with five carbon atoms. Isopentane is an extremely volatile and extremely flammable liquid at room temperature and pressure.
It's farmula is: C5H12</span>
Answer:
that is a solid and that there are other ways to make a fire?
