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Art [367]
3 years ago
12

Determine the number of molecules in 43.9 g of carbon tetrachloride

Chemistry
1 answer:
ddd [48]3 years ago
7 0

Answer: There are about 0.28 molecules in 43.9 g of carbon tetrachloride. If you are rounding up, it would be 0.3

Explanation:

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Need help fast please 20 points
artcher [175]

Answer:

gamma radiation

Explanation:

on edge!

5 0
3 years ago
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HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?
Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0
3 years ago
The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6Li + N2 mc007-1.jpg 2Li3N If 12 mol of lith
andrew11 [14]

Answer is: 4.0 mol of lithium nitride would be produced.

Balanced chemical reaction: 6Li + N₂ → 2Li₃N.

n(Li) = 12 mol; amount of substance.

From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).

n(Li₃N) = n(Li) ÷ 3.

n(Li₃N) = 12 mol ÷ 3.

n(Li₃N) = 4 mol; amount of lithium nitride.

4 0
3 years ago
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Gaseous butane CH3CH22CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is
SOVA2 [1]

Answer:

10.56 g

Explanation:

C4H10(g) + 13/2O2 (g) -------> 4CO2(g) + 5H2O(l)

Number of moles of butane = 3.49g/ 58 g/mol = 0.06 moles

1 mole butane yields 4 moles of CO2

0.06 moles of butane = 0.06 × 4/1 = 0.24 moles of CO2

Number of moles of oxygen = 17.1g/32g/mol = 0.53 moles of oxygen

6.5 moles of oxygen yields 4 moles of CO2

0.53 moles of oxygen yields 0.53 × 4/6.5 =0.33 moles of CO2

Butane is the limiting reactant

Theoretical yield of CO2 = 0.24 moles × 44g/mol = 10.56 g

3 0
3 years ago
C. If an electron is added to the outer shell, how will this affect the charge and volume of the atom?
Norma-Jean [14]

Answer:

An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion.

8 0
3 years ago
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