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kherson [118]
3 years ago
15

A small bag of trail mix contains 3 cups of dried fruit and 4 cups of almonds.A large bag contains 41/2 cups of dried fruit and

6 cups of almonds. Write and solve a system of linear equations to find the price of 1 cup of dried fruit and 1 cup of almonds if the Price of small bag is $6 while $9 for large bag.  
      
Mathematics
1 answer:
Juliette [100K]3 years ago
3 0
Let's call:
f = price of 1 cup of dried fruit
a = price of 1 cup of almonds

In order to build the linear system, you need to consider that the total price of a bag is given by the sum of the price of cups times the number of cups in each bag, therefore:

\left \{ {{3f + 4a = 6} \atop {41/2 f + 6a = 9 }} \right.

Solve for a in first equation:
a = (6 - 3f) / 4

Then substitute in the second equation:
41/2 f + 6 · (6 - 3f) / <span>4 = 9
41/2 f + 9 - 9/2 f = 9
16 f = 0
f = 0

Now, substitute this value in the formula found for a:
</span>a = (6 - 3·0) / <span>4
   = 3/2 = 1.5

Hence, the cups of dried fruit are free and 1 cup of almond costs 1.5$</span>

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Luda [366]

1) The point slope form and slope intercept form of 3x + 4y = -12 are y+1=\frac{-3}{4}\left(x+\frac{8}{3}\right) and y= \frac{-3}{4}x-3 respectively

And slope is \frac{-3}{4} and y -intercept is -3

2) The point slope form and slope intercept form of -2x - 3y = 6 are y+1=-\frac{2}{3}\left(x+\frac{3}{2}\right) and y=-\frac{2}{3} x-2 respectively

And slope is \frac{-2}{3} and y-intercept is -2

<u>Solution:</u>

Given, two equations are 3x + 4y = - 12 ⇒ (1) and – 2x – 3y = 6 ⇒ (2)

We have to find the point slope form and slope intercept form, and have to indicate the slope and y-intercept.

<em><u>The point slope form is given as:</u></em>

y-y_{1}=m\left(x-x_{1}\right)

Where "m" is the slope of the line

<em><u>The slope-intercept form is given as:</u></em>

y = mx + c

Where "c" is the y-intercept

<em><u>1) Solving 3x + 4y = -12</u></em>

Given equation is 3x + 4y = -12

On rearranging the terms, we get,

\begin{array}{l}{4 y=-3 x-12} \\\\ {\rightarrow y=\frac{-3}{4}-3}\end{array}

Hence the slope intercept form is y=\frac{-3}{4}-3

\text { where slope is }-\frac{3}{4} \text { and } y-\text { intercept is }-3

\text { Point slope form i.e. } y-y_{1}=m\left(x-x_{1}\right)

\begin{array}{l}{3 x+4 y=-12} \\\\ {\rightarrow 4 y=-3 x-12} \\\\ {\rightarrow y=\frac{-3}{4} x-3} \\\\ {\rightarrow y=\frac{-3}{4} x-2-1} \\\\ {\rightarrow y+1=\frac{-3}{4}\left(x+\frac{8}{3}\right)}\end{array}

<em><u>2) Solving -2x – 3y = 6 </u></em>

Slope intercept form is given as:

-2 x-3 y=6 \rightarrow-3 y=2 x+6 \\\\\rightarrow y=-\frac{2}{3} x-2

\text { where slope is }-\frac{2}{3} \text { and } y-\text { intercept is }-2

Point slope form is given as:

\begin{array}{l}{-2 x-3 y=6 \rightarrow-3 y=2 x+6} \\\\ {\rightarrow y=-\frac{2}{3} x-2} \\\\ {\rightarrow y=-\frac{2}{3} x-1-1} \\\\ {\quad \rightarrow y+1=-\frac{2}{3}\left(x+\frac{3}{2}\right)}\end{array}

Hence the required slope and y-intercept are found

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If f(x)=|x|+9 and g(x)=-6, which describes the value of (f+g)(x)
Marysya12 [62]
F(x) = |x| + 9
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(f + g)(x) = |x| + 9 - 6 = |x| + 3
(f + g)(x) = |x| + 3
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