The answer is the last one
Answer: not be able to stop in time to miss the object
Explanation:
The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.
When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.
This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.
Answer:
9.8 × 10⁴Pa
Explanation:
Given:
Velocity V₁ = 12m/s
Pressure P₁ = 3 × 10⁴ Pa
From continuity equation we have
ρA₁V₁ = ρA₂V₂
A₁V₁ = A₂V₂
making V₂ the subject of the equation;
the pipe is widened to twice its original radius,
r₂ = 2r₁
then the cross-sectional area A₂ = 4A₁
⇒ 
This implies that the water speed will drop by a factor of 
because of the increase the pipe cross-sectional area.
The Bernoulli Equation;
Energy per unit volume before = Energy per unit volume after
p₁ + 
ρV₁² + ρgh₁ = p₂ + ρV₂² + ρgh₂
Total pressure is constant and 
= P = ρV₂²ρV²
p₁ + ρV₁² = p₂ + ρV₂²
Making p₂ the subject of the equation above;
p₂ = p₁ + ρV₁² - ρV₂²
But 
so,
p₂ = p₁ + ρV₁² - ρ
p₂ = 3.0 x 10⁴ + ( × 1000 × 12²) - ( × 1000 × 12²/4² )
P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³
P₂ = 9.79 × 10⁴Pa
P₂ = 9.8 × 10⁴Pa
<h2>Answer:</h2>
<em>Metals are both good heat conductors and good electrical conductors because of the </em><em>looseness of outer electrons in metal atoms</em>
_________________________
Unlike nonmetals that are insulators, most metals are both good heat conductors and good electrical conductors. This is because within a solid metal there is one or more outer electrons in each atom that become detached and can move freely through the solid metal, but <em>what about the other electrons?</em> Well, the
y remain bound to the positively charged nuclei, and bound within the material in almost fixed positions. On the other hand, insulators are material having few, very few or no electrons that are allowed to move freely through the material.
Answer:
0.532
Explanation:
Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ
First, find your variables.
λ = 580 · 10^-9
d = 0.000125
m = 2
Next, fill in the equation.
d sin (θ) = m λ
(0.000125) sin (θ) = (2) (580·10^-9)
Then isolate your variable.
θ = arcsin ( (2)(580·10^-9) / (0.000125) )
Run your equation and you will end up with 0.53171246 , which rounds to 0.532.
The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.
I hope this helps :D
