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harina [27]
3 years ago
10

The table shows a chemical equation and the dimensional analysis used by a student to calculate the number of moles of Ba3N2 req

uired to produce 9.2 moles of Ba(OH)2. Student's Dimensional Analysis Chemical Equation Dimensional Analysis Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3 9.2 mol of Ba(OH)2 x 3 mol of Ba(OH)2 / 1 mol of Ba3N2 What is the error in the dimensional analysis? (1 point) a 1 mol of Ba3N2 should be replaced with 3 mol of Ba3N2 b 3 mol of Ba(OH)2 should be replaced with 1 mol of Ba(OH)2 c 3 mol of Ba(OH)2 and 1 mol of Ba3N2 should be interchanged d 9.2 mol of Ba(OH)2 and 1 mol of Ba3N2 should be interchanged
Chemistry
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

c 3 mol of Ba(OH)₂ and 1 mol of Ba₃N₂ should be interchanged  

Explanation:

              Ba₃N₂ + 6H₂O → 3Ba(OH)₂ + 2NH₃

n/mol:                                      9.2

\text{Moles of Ba$_{3}$N}_{2} = \text{9.2 mol Ba(OH)}_{2} \times \dfrac{\text{1 mol Ba$_{3}$N}_{2}} {\text{3 mol Ba(OH)}_{2}}= \text{x mol Ba$_{3}$N}_{2}

They want to find moles of Ba₃N₂, so that should be in the numerator of the conversion factor,

Moles of Ba(OH)₂ should be in the denominator to cancel the units in 9.2 mol Ba(OH)₂,

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You burn 270 grams of glucose during respiration. How
BlackZzzverrR [31]

Answer:

396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.

Explanation:

To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;

C6H12O6 + 6O2 -------> 6CO2 + 6H2O

1 mole of C6H12O6 reacts to form 6 moles of CO2

Then, calculate the molar mass of the two variables;

Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol

Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol

Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles

1* 180 g of glucose yields 6 * 44 g of CO2

180 g of glucose = 264 g of CO2

If 270 g of glucose were to be used, how many grams of CO2 will be produced;

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180 g of glucose = 264 g of CO2

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In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.

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