Answer:
![\Delta _RH=4x10^{-3}\frac{kJ}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D4x10%5E%7B-3%7D%5Cfrac%7BkJ%7D%7Bmol%7D)
Explanation:
Hello,
In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:
![\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D%5Cfrac%7B12J%7D%7B3mol%7D%20%3D4%5Cfrac%7BJ%7D%7Bmol%7D)
Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:
![\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D4%5Cfrac%7BJ%7D%7Bmol%7D%2A%5Cfrac%7B1kJ%7D%7B1000J%7D%20%3D4x10%5E%7B-3%7D%5Cfrac%7BkJ%7D%7Bmol%7D)
Best regards.
2H₂(g) + O₂(g) ⇄ 2H₂O(l)
Δngas = 0 - (2 +1)
= -3
<h3>
What is Δngas?</h3>
The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.
Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.
<h3>
Definition of equilibrium</h3>
When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.
Learn more about Equilibrium
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The appropriate response is Mg2+. It has the smallest radius the would mean the littlest separation from it's the furthest shell to the core
Since magnesium has one less shell that calcium, Mg would have a little nuclear range. Besides, a particle of a component will have a little nuclear sweep than it's molecule be utilized as a part of its particle frame it has lost a shell