FeS + H₂O → FeO + H₂S
Explanation:
Iron Sulfide = FeS
Water = H₂O
FeS + H₂O → FeO + H₂S
To balance this equation, we can use a mathematical method. This involves solving simple algebraic equations
aFeS + bH₂O → cFeO + dH₂S
a,b,c and d are the coefficients needed to balance up the equation:
Conserving Fe: a = c
S: a = d
H: 2b = 2d
O: b = c
let a = 1, c= 1, b = 1 d = 1
The balanced equation is: FeS + H₂O → FeO + H₂S
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Balanced equation brainly.com/question/2612756
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Percent error is [(abs(experimental - actual))/(actual)] * 100
(38.0 - 40.0 ) / 40.0 = 2.0 / 40 = 0.05
0.05 * 100 = 5
since there are 2 sigfigs, the answer is 5.0 %
I made the 2 positive since the absolute value of 38.0 - 40.0 was taken
There are only 2 sigfigs because of the subtraction of 38.0 - 40.0 gives 2.0, only 2 sigfigs
In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure. They are created by moving electrons in double or triple bonds, and not atoms.
Phenol,
and methanol,
both are alcohols that contain an
group attached to carbon atom.
Due to loss of 1
from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1
it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.
The structures of the anions resulting from loss of 1
from phenol and methanol is shown in the image.