Hi there!
Recall:
Impulse = Change in momentum
I = Δp = mΔv = m(vf - vi)
Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.
Plug in the givan values:
Δp = 1.5(-10 - 12) = -33 Ns
**OR, the magnitude: |-33| = 33 Ns
Answer:
In my opinion I think that the answer is C sorry If I get this wrong.
Answer:
v = -5 m/s
Explanation:
It is given that,
The initial velocity of the ball, u = 25 m/s
We need to find its velocity after 2 seconds in the air.
Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.
v = u + at
Here, a = -g
v = u -gt
Putting all the values,
v = 25 - (10)(3)
= 25-30
= -5 m/s
So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.
