A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i
2 answers:
We can solve the problem by using the first law of thermodynamics:
where
is the variation of internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system
In this problem, the heat absorbed by the system is Q=+44 J, and the increase in internal energy is
. So we can rearrange the equation to calculate the work done:
and the work is positive, which means that it is done by the system on the surrounding.
where
Q is the heat absorbed by the system
W is the work done by the system
In this problem, the heat absorbed by the system is Q=+44 J, and the increase in internal energy is
and the work is positive, which means that it is done by the system on the surrounding.
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Answer:
a)
b)
c)
d) Displacement = 22 m
e) Average speed = 11 m/s
Explanation:
a)
Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:
Therefore, acceleration is
b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:
c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:
d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):
Displacement =
e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:
Average velocity =