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N76 [4]
4 years ago
12

A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i

s 32 joules. How much energy was used by the system to do useful work?
Physics
2 answers:
Minchanka [31]4 years ago
7 0

12 j is correct on edge

Lelu [443]4 years ago
4 0
We can solve the problem by using the first law of thermodynamics:
\Delta U = Q-W
where
\Delta U is the variation of internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system

In this problem, the heat absorbed by the system is Q=+44 J, and the increase in internal energy is \Delta U = +32 J. So we can rearrange the equation to calculate the work done:
W=Q-\Delta U=44 J-32 J=+12 J
and the work is positive, which means that it is done by the system on the surrounding.
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8 0
3 years ago
A ball dropped by melissa is falling downward toward the floor
Artist 52 [7]
What is the question
3 0
3 years ago
You want to reduce your energy bills.
aleksandr82 [10.1K]

Answer:

A. 100 Watts

B. 12 Watts

C. the first bulb

Explanation:

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6000J/60seconds = 100J/s or 100W

B. Another formula for power is Current * Voltage

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6 0
3 years ago
The blade of a windshield wiper moves through an angle of 180.0 degrees in 0.500 s. The tip of the blade moves on the arc of a c
sweet-ann [11.9K]

Answer:

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We have given time taken to cover 180° is 0.5 sec

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Centripetal acceleration will be equal to a_c=\frac{v^2}{r}=\frac{3.2656^2}{1}=10.66m/sec^2

So centripetal acceleration will be equal to 10.66m/sec^2

7 0
4 years ago
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