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Valentin [98]
3 years ago
5

A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

Physics
2 answers:
andriy [413]3 years ago
7 0
Ke =(1/2 )mv^2
1/2(90*4)^2
720
Have a nice day
guajiro [1.7K]3 years ago
6 0

Answer:

Ek = 720J

Explanation:

Ek = 0.5mv^2

Ek = 0.5(90)(4)^2

Ek = 720J

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For small angles, does the pendulum's period of oscillation depend on initial angular displacement from equilibrium? Explain.
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No, the pendulum's period of oscillation does not depend on initial angular displacement.

Explanation:

Given that,

For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.

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Law of motion that says for every action there is an equal and opposite
hodyreva [135]

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The tension at which a fishing line snaps is commonly called the line's strength .what minimum strength is needed for a line tha
marusya05 [52]
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Start converting all the information to the SI.

mass, m = 19 lb * [1kg/2.2046lb] = 8.618 kg

speed: 9.2 ft/s * .3048m/ft = .2.80 m/s

distance to stop: 4.4 in * [2.54cm/in]*[1m/100cm] = 0.11176 m

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Answer: 302.5 N

 
3 0
3 years ago
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