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MissTica
3 years ago
14

Calculate the defect of helium nucleus​

Chemistry
1 answer:
Tcecarenko [31]3 years ago
3 0

1 amu=1.67×10  

−27

kg

Using this and Einsteins relation, we get the energy equivalent to the rest mass as:

E=mc  

2

=(1.67×10  

−27

×0.0304)×(3×10  

8

)  

2

=4.569×10  

−12

J

Converting this energy in electron volts.

E=  

1.6×10  

−19

 

4.569×10  

−12

 

​  

=28MeV

This is per nucleon of Helium. One Helium nucleus has four nucleons.

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A visual representation of covalent bonding which represents the valence shell electrons in the molecule is said to be a Lewis structure. The lines represents the shared electron pairs and dots represents the electrons that are not involved in the bonding i.e lone pairs.

Number of valence electrons in each atom:

For Carbon, C = 4

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The Lewis structure of CH_3NC is shown in the attached image.

The formula of calculating formula charge = FC = VE - NE- \frac{BE}{2}   -(1)

where, F.C is formal charge, V.E is number of valence electrons, N.E is number of non-bonding electrons and B.E is number of bonding electrons.

Now, calculating the formal charge:

For C on left side:

FC = 4 - 0- \frac{8}{2} = 0

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FC = 5 - 0- \frac{8}{2} = +1

For C on right side:

FC = 4 - 2- \frac{6}{2} = -1

The formula charge of each atom other than hydrogen is shown in the attached image.


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