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Inessa05 [86]
3 years ago
11

A sample of neon occupies a volume of 461 mL at 1 atm and 273 K. What will be the volume of the neon when the pressure is reduce

d to 0.92 atm? (0.501 L)
Chemistry
1 answer:
Softa [21]3 years ago
4 0

Answer:

0.501 L

Explanation:

To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".

                           V∝ 1/P

                           V= K/P

                            VP=K

Here the K is proportionality constant.

so,

             P1V1 = P2V2

P= pressure

V= volume

Given data:

P1= 1 atm

V1= 461 mL

P2= 0.92 atm

V2= ? (L)

To solve this problem we have to convert the mL into L first.

1 L = 1000 mL

461/1000= 0.461 L

Now we will put the values in the equation,

P1V1 = P2V2

V2= P1V1/ P2

V2= 1 atm × 0.461 L / 0.92 atm

V2= 0.501 L

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In this case, by using the general gas law, that allows us to understand the pressure-volume-temperature relationship as shown below:

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a) When the reaction takes place a yellow precipitate will be formed.

b) The law of conservation of mass is true.

<u>Explanation:</u>

a) When a lead nitrate solution is mixed with a potassium chromate solution, a yellow precipitate containing lead forms according to the equation:

Pb(NO_3)_2 (aq) + K_2CrO_4 (aq) → 2 KNO_3 (aq) + PbCrO_4(s).

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From the given table we know the mass of reactants and its products.

Law of conservation of mass is a principle when a reaction takes place in a closed system, the mass of the products and reactants in the system doesn't change.

⇒The sum of the mass of the reactants = The sum of the mass of the products.

The sum of the reactants = 128.71+128.97.

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