This depends if this is Distance or Displacement. If this is distance; Scalar, vector; Vector.
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Answer:
b) 450 V
Explanation:
We are given that
Total charge, q=10nC=

Radius, r=20 cm=
1 m=100 cm
x=15 cm=0.15 cm
We have to find the electrical potential 15 cm above the center of a uniform charge density disk .
We know that


Where 

Electric potential,
Where 
Using the formula


Hence, option b is correct.
Answer:

Explanation:
given,
total deflection = 4.12 cm
Electric field = 1.1 ×10³ V/m
plate length = 6 cm
distance between them = 12 cm
using formula

q = 1.6 × 10⁻¹⁹ C
m = 9.11 x 10⁻³¹ kg
d = 0.06 m
L = 0.12 m

v_0 = 6496355.63 m/s




Answer:

Explanation:
The amplitude of he combined wave is:

A, is the amplitude from the identical harmonic waves
B, is the amplitude of the resultant wave
θ, is the phase, between the waves
The amplitude of the combined wave must be 0.6A:

For simplicity, let's call vector B-A vector C Then C is
Cx = (-6.1 - 2.2)
Cy = (-2.2 - (-6.9)) Or,
Cx = -8.3 Cy = 4.7
The magnitude is found with the Pythagorean theorem
||C|| = √(-8.3² + 4.7²) = 9.538