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Answer:
the volume decreases at the rate of 500cm³ in 1 min
Explanation:
given
v = 1000cm³, p = 80kPa, Δp/t= 40kPa/min
PV=C
vΔp + pΔv = 0
differentiate with respect to time
v(Δp/t) + p(Δv/t) = 0
(1000cm³)(40kPa/min) + 80kPa(Δv/t) = 0
40000 + 80kPa(Δv/t) = 0
Δv/t = -40000/80
= -500cm³/min
the volume decreases at the rate of 500cm³ in 1 min
(a) The magnitude of the force that the magnetic field exerts on the loop is 0.042 N.
(b) The direction of the force that the magnetic field exerts on the loop will be out of the plane.
<h3>
Magnetic force exerted on the loop</h3>
F = BIL
where;
- I is current in the loop
- L is length of the loop
emf = BVb
where;
- b is breadth of the loop
- V is velocity
- B is magnetic field
emf = 2.6 x 3 x 0.018 = 0.1404 V
Current in the loop, I = emf/R = 0.1404/0.8 = 0.18 A
<h3>Magnetic force</h3>
F = BIL
where;
F = 2.6 x 0.18 x 0.09 = 0.042 N
<h3>Direction of the force</h3>
The direction of the force that the magnetic field exerts on the loop will be out of the plane.
Learn more about magnetic force here: brainly.com/question/13277365
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Answer:
New resistance = 243 ohm
Explanation:
Given:
Current resistance = 27 ohm
Computation:
The wire is extended to three times its initial size, and its cross-section is therefore shortened to one-third of how it used to be. We found the current resistance to be 3x3= 9 times
So,
New resistance = 27 x 9
New resistance = 243 ohm
