Answer:
pCl⁻ = 0.54
Explanation:
First we <u>calculate how many Cl⁻ moles are coming from each substance</u>, using the <em>given volumes and concentrations</em>:
- 0.12 M NaCl * 0.10 L = 0.012 mol NaCl = 0.012 mol Cl⁻
- 0.18 M MgCl₂ * 0.23 L = 0.0414 mol MgCl₂ = (0.0414 * 2) 0.0828 mol Cl⁻
The final volume of the mixture is = 0.10 L + 0.23 L = 0.33 L
Now we <u>calculate [Cl⁻]</u>, using the<em> total number of Cl⁻ moles and the final volume:</em>
- [Cl⁻] = (0.012 mol + 0.0828 mol) / 0.33 L = 0.29 M
Finally we <u>calculate the pCl⁻ of the resulting solution</u>:
Answer:
Save the *minerals* used to extract metals.
Answer:
1.17 mol
Explanation:
Step 1: Write the balanced equation
2 Al + 6 HCl → 2 AlCl₃ + 3 H₂
Step 2: Calculate the moles corresponding to 85.0 g of HCl
The molar mass of HCl is 36.46 g/mol.
85.0 g × 1 mol/36.46 g = 2.33 mol
Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl
The molar ratio of HCl to H₂ is 6:3.
2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂
A division or split
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