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Inessa05 [86]
3 years ago
8

Translate this problem to an equation and solve. The product of 2 positive consecutive even integers is 48. What is the smaller

number?
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0
Let x represent the first even integer: x = 2(k) → y = 2k
Let y represent the second even integer: y = 2(k + 1)  → y = 2k + 2

   x  ·     y        = 48
(2k) · (2k + 2) = 48
 4k² + 4k - 48  = 0
 4(k² + k - 12)  = 0
4 (k + 3)(k - 2) = 0
k = -3, k = 2  (Note: POSITIVE integers so k = -3 is ruled out)

x = 2k → x = 2(2) → x = 4
y = 2(k + 1) → y = 2(2 + 1) → y = 2(3) → y = 6

The smaller number (x) is 4
        


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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

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\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
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nexus9112 [7]

Answer:

Since the roots are 3, -4 then we must put

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(x -3) * (x +4) = 0 then multiplying

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Step-by-step explanation:

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WARRIOR [948]
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Now take this number and divide by the original number (first):

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This is 1.4, let's convert this to a percentage.
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1.4 × 100

The answer is 140%
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Step-by-step explanation:

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