The compound that would be most reactive is Ethyne (answer A)
<u><em> explanation</em></u>
- Ethyne is the most unsaturated among the four compounds ( <em> it has a triple bond between the two carbon atoms) .</em>
- The triple bond in ethyne is made up of 1 sigma bond and 2π bond.
- <em>The 2π bond are weaker and can easily break which make Ethyne more reactive than Ethene, methane and Ethane.</em>
Answer: The question has some details missing. here is the complete question ; An analytical chemist is titrating 88.4 mL of a 0.2700 M solution of ammonia (NH3 with a 0.4300 M solution of HNO3. The pK, of ammonia is 4.74 Calculate the pH of the base solution after the chemist has added 66.3 mL of the HNO3 solution to it . Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution
Explanation:
Given ;
- number of moles of base = 88.4 x 0.2700 = 23.868
- number of moles of acid = 0.4300 x 66.3 = 28.509
- This was after the equivalence point, as such net moles of acid = 28.509 - 23.868 = 4.641mol
- total volume of solution = 88.4 + 66.3 = 154.7mL
- Concentration of Acid = moles/volume = 4.641/154.7 = 0.03M
- From pH = -log[H^+] = -Log[0.03]
Answer:
<em>56.4 m</em>
<em></em>
Explanation:
volume increases by factor of 6, i.e
= 6
Initial temperature T1 at bottom of lake = 5.24°C = 278.24 K
Final temperature T2 at top of lake = 18.73°C = 291.73 K
NB to change temperature from °C to K we add 273
Final pressure P2 at the top of the lake = 0.973 atm
Initial pressure P1 at bottom of lake = ?
Using the equation of an ideal gas
= 
P1 =
= 
P1 = 5.57 atm
5.57 atm = 5.57 x 101325 = 564380.25 Pa
Density Ρ of lake = 1.02 g/
= 1020 kg/
acceleration due to gravity g = 9.81 
Pressure at lake bottom = pgd
where d is the depth of the lake
564380.25 = 1020 x 9.81 x d
d =
= <em>56.4 m</em>
<u>Answer:</u> The mass of potassium superoxide required is 142.2 grams
<u>Explanation:</u>
The chemical equation for the reaction of potassium superoxide with water follows:

Number of moles of potassium superoxide reacted = 2 moles for given amount of heat released
To calculate the mass for given number of moles, we use the equation:

Molar mass of potassium superoxide = 71.1 g/mol
Moles of potassium superoxide = 2 moles
Putting values in above equation, we get:

Hence, the mass of potassium superoxide required is 142.2 grams
Answer:
pH = 9.03
Explanation:
The equilibrium of the NH₄Cl / NH₃ buffer in water is:
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Initial moles of both NH₃ and NH₄⁺ are:
0.100L ₓ (0.20 mol / L) = <em>0.0200 moles </em>
The NH₃ reacts with HCl producing NH₄⁺, thus:
NH₃ + HCl → NH₄⁺ + Cl⁻
<em>That means, moles of HCl added to the solution are the same moles are consumed of NH₃ and produced of NH₄⁺</em>
Moles added of HCl were:
0.025L ₓ (0.20mol / L) = 0.0050 moles of HCl. Thus, final moles of NH₃ and NH₄⁺ are:
NH₃: 0.0200 moles - 0.0050 moles = 0.0150 moles
NH₄⁺: 0.0200 moles + 0.0050 moles = 0.0250 moles.
Using H-H equation for bases:
pOH = pKb + log [NH₄⁺] / [NH₃]
<em>Where pKb is -log Kb =</em><em> 4.745</em><em>.</em>
Replacing:
pOH = 4.745 + log 0.0250mol / 0.0150mol
pOH = 4.967
As pH = 14- pOH
<em>pH = 9.03</em>
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