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monitta
3 years ago
13

Determine the electron-group arrangement, molecular shape, and ideal bond angle for the following molecule: PH3 Electron-group a

rrangement: tetrahedral trigonal pyramidal V-shaped trigonal planar Molecular shape: tetrahedral trigonal pyramidal T-shaped bent Ideal bond angle: degrees.

Chemistry
1 answer:
Alecsey [184]3 years ago
5 0

Answer:

The molecular shape and ideal bond angle of the PH_{3} is trigonalbipyramidal and 109.5^{o} respectively.

Explanation:

The structure of  PH_{3}  is as follows.(in attachment)

From the structure,

Phosphor atom has one lone pair and three hydrogens are bonded by six electrons.

Therefore, total electrons invovled in the formation PH_{3}  is eight.

Hence, four electron groups which indicate the tetrahedral shape. But one pair is lone pair i.e, present on the phosphor atom.

Therefore, ideal geometry of the PH_{3}  molecule is <u>Trigonalbipyramidal.</u>

The ideal angle of trigonalbipyrmidal is 109.5^{o}.

All three bonds of P-H has 109.5^{o}.

Therefore, ideal bond angle is <u>109.5^{o}.</u>

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Which of the following compounds would you expect to be the most reactive?
9966 [12]

  The   compound  that  would  be   most   reactive  is   Ethyne  (answer A)


   <u><em>  explanation</em></u>

  •    Ethyne   is the  most    unsaturated  among the four  compounds  ( <em> it  has a triple bond between  the two carbon atoms) .</em>

  • The  triple  bond in ethyne   is made up  of 1  sigma  bond  and  2π   bond.
  • <em>The 2π  bond  are  weaker   and can  easily break   which  make  Ethyne  more  reactive than  Ethene, methane  and Ethane.</em>

4 0
3 years ago
An analytical chemist is titrating of a solution of ammonia with a solution of . The of ammonia is . Calculate the pH of the bas
harina [27]

Answer: The question has some details missing. here is the complete question ; An analytical chemist is titrating 88.4 mL of a 0.2700 M solution of ammonia (NH3 with a 0.4300 M solution of HNO3. The pK, of ammonia is 4.74 Calculate the pH of the base solution after the chemist has added 66.3 mL of the HNO3 solution to it . Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution

Explanation:

Given ;

  • number of moles of base = 88.4 x 0.2700 = 23.868
  • number of moles of acid = 0.4300 x 66.3 = 28.509
  • This was after the equivalence point, as such net moles of acid = 28.509 - 23.868 = 4.641mol
  • total volume of solution = 88.4 + 66.3 = 154.7mL
  • Concentration of Acid = moles/volume = 4.641/154.7 = 0.03M
  • From pH = -log[H^+] = -Log[0.03]
  • pH = 1.52

7 0
4 years ago
(a) show that the pressure exerted by a fluid P (in pascals) is given by P= hdg, where h is the column of the fluid in metres, d
Murrr4er [49]

Answer:

<em>56.4 m</em>

<em></em>

Explanation:

volume increases by factor of 6, i.e \frac{V2}{V1} = 6

Initial temperature T1 at bottom of lake =  5.24°C = 278.24 K

Final temperature T2 at top of lake = 18.73°C = 291.73 K

NB to change temperature from °C to K we add 273

Final pressure P2 at the top of the lake = 0.973 atm

Initial pressure P1 at bottom of lake = ?

Using the equation of an ideal gas

\frac{P1V1}{T1} = \frac{P2V2}{T2}

P1 = \frac{P2V2T1}{V1T2} = \frac{0.973*6*278.24}{291.73}

P1 = 5.57 atm

5.57 atm = 5.57 x 101325 = 564380.25 Pa

Density Ρ of lake = 1.02 g/cm^{3} = 1020 kg/m^{3}

acceleration due to gravity g = 9.81 m/s^{2}

Pressure at lake bottom = pgd

where d is the depth of the lake

564380.25 = 1020 x 9.81 x  d

d = \frac{564380.25}{10006.2} = <em>56.4 m</em>

3 0
4 years ago
Potassium superoxide is a yellow paramagnetic solid that reacts with water according to the following balanced equation. Calcula
babunello [35]

<u>Answer:</u> The mass of potassium superoxide required is 142.2 grams

<u>Explanation:</u>

The chemical equation for the reaction of potassium superoxide with water follows:

2KO_2+H_2O\rightarrow KOH+KHO_2+O_2;\Delta H=2405J

Number of moles of potassium superoxide reacted = 2 moles for given amount of heat released

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of potassium superoxide = 71.1 g/mol

Moles of potassium superoxide = 2 moles

Putting values in above equation, we get:

2mol=\frac{\text{Mass of potassium superoxide}}{71.1g/mol}\\\\\text{Mass of potassium superoxide}=(2mol\times 71.1g/mol)=142.2g

Hence, the mass of potassium superoxide required is 142.2 grams

4 0
3 years ago
100 mL of a buffer that consists of 0.20 M NH3 and 0.20 M NH4Cl is titrated with 25 mL of 0.20 M HCl. Calculate the pH of the re
Marrrta [24]

Answer:

pH = 9.03

Explanation:

The equilibrium of the NH₄Cl / NH₃ buffer in water is:

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

Initial moles of both NH₃ and NH₄⁺ are:

0.100L ₓ (0.20 mol / L) = <em>0.0200 moles </em>

The NH₃ reacts with HCl producing NH₄⁺, thus:

NH₃ + HCl → NH₄⁺ + Cl⁻

<em>That means, moles of HCl added to the solution are the same moles are consumed of NH₃ and produced of NH₄⁺</em>

Moles added of HCl were:

0.025L ₓ (0.20mol / L) = 0.0050 moles of HCl. Thus, final moles of NH₃ and NH₄⁺ are:

NH₃: 0.0200 moles - 0.0050 moles = 0.0150 moles

NH₄⁺: 0.0200 moles + 0.0050 moles = 0.0250 moles.

Using H-H equation for bases:

pOH = pKb + log [NH₄⁺] / [NH₃]

<em>Where pKb is -log Kb =</em><em> 4.745</em><em>.</em>

Replacing:

pOH = 4.745 + log 0.0250mol / 0.0150mol

pOH = 4.967

As pH = 14- pOH

<em>pH = 9.03</em>

<em />

6 0
3 years ago
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