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monitta
3 years ago
13

Determine the electron-group arrangement, molecular shape, and ideal bond angle for the following molecule: PH3 Electron-group a

rrangement: tetrahedral trigonal pyramidal V-shaped trigonal planar Molecular shape: tetrahedral trigonal pyramidal T-shaped bent Ideal bond angle: degrees.

Chemistry
1 answer:
Alecsey [184]3 years ago
5 0

Answer:

The molecular shape and ideal bond angle of the PH_{3} is trigonalbipyramidal and 109.5^{o} respectively.

Explanation:

The structure of  PH_{3}  is as follows.(in attachment)

From the structure,

Phosphor atom has one lone pair and three hydrogens are bonded by six electrons.

Therefore, total electrons invovled in the formation PH_{3}  is eight.

Hence, four electron groups which indicate the tetrahedral shape. But one pair is lone pair i.e, present on the phosphor atom.

Therefore, ideal geometry of the PH_{3}  molecule is <u>Trigonalbipyramidal.</u>

The ideal angle of trigonalbipyrmidal is 109.5^{o}.

All three bonds of P-H has 109.5^{o}.

Therefore, ideal bond angle is <u>109.5^{o}.</u>

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3 years ago
Which statements are true? Check all that apply. Check all that apply. The higher the temperature, the more soluble most ionic s
snow_lady [41]

Answer:

The higher the temperature, the more soluble most ionic solids are in water

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Explanation:

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8 0
3 years ago
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Igoryamba

Answer:

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<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>

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A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of heliu
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Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: V_{1} = 2.25 L,     n_{1} = 9.0 mol

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Formula used to calculate the moles of helium are as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\

Substitute the values into above formula as follows.

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Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

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to separate objects or ideas into group based on ways they are alike

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