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never [62]
3 years ago
15

Lead is listed below zinc in the activity series.

Chemistry
2 answers:
nikdorinn [45]3 years ago
3 0

Answer:

Zn+Pb(NO3)2→Zn(NO3)2+Pb

Natali5045456 [20]3 years ago
3 0

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

When lead nitrate is reacted with zinc metal, it leads to the formation of zinc nitrate and solid lead.

The chemical equation for the above reaction follows:

Pb(NO_3)_2(aq.)+Zn(s)\rightarrow Zn(NO_3)_2(aq.)+Pb(s)

As, zinc lies above in the reactivity series than lead, so it will easily displace lead from its chemical reaction.

Hence, the chemical equation is written above.

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Branched  structure  isomer    has  weak  intermolecular  forces  of attraction  as  compared  to  straight  chain  isomers.  In addition the  branched  isomer  has  a  low boiling point as  compared to  straight chain isomers. Since   boiling require  the of  the  intermolecular  forces tend to have  lower  boiling  point   than straight chain
8 0
4 years ago
Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

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Concentration of (OH⁻) = 0.3 - 2x

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                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
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When the reaction equation is:

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we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

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so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


∴ mass = 0.68 moles* 120 g/mol = 81.6 g
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Answer:

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