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Ilia_Sergeevich [38]
3 years ago
5

A balloon has a maximum capacity of 1700 m3. On a cool morning (temperature = 10°c, some hot-air balloonists start filling their

balloon with air until it occupies three-fourths of the maximum possible volume. Then, they turn on the propane burner to fill the balloon to its complete volume of 1700 m3. The temperature at which the air fills the balloon to its maximum capacity is:
Chemistry
1 answer:
bulgar [2K]3 years ago
7 0

V1/T1 = V2 / T2

V1 = 3/4(1700) = 1275

T1 = 10 + 273.15 = 283.15

V2 = 1700

T2 = V2T1

T2 = (1700) (283.15) / 1275

T2 = 377.53 K

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Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
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Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0
3 years ago
How to tell which element is oxidized in a reaction?
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If in a redox reaction oxidation state of elements decreases or looses electron(s), the element is said to be oxidized. Hope this helps you!
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How many grams of NaHCO3are in 3.75 x 10 ^-3 moles of NaHCO3<br><br> PLS HELP DUE TODAY
hodyreva [135]

Answer: m= 3.15x10-3 g NaHCO3

Explanation: To find the mass of NaHCO3 we will use the relationship between moles and molar mass. The molar mass of NaHCO3 is 84 g.

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= 3.15x10-3 g NaHCO3

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