Answer: The answer is the second choice.
Explanation:
Answer:
The answer to your question is AgCl
Explanation:
Data
Silver = Ag = 75%
Chlorine = Cl = 25%
1.- Convert percent numbers to grams
Silver = 75 g
Chlorine = 25 g
2.- Calculate the moles of each element
Mass number Ag = 108 g
Mass number Cl = 35.5 g
108 g of Ag ------------------ 1 mol
75 g of Ag ------------------ x
x = (75 x 1) / 108
x = 75 / 108
x = 0.69 moles
35.5 g of Cl ------------------ 1 mol
25 g of Cl ----------------- x
x = (25 x 1) / 35.5
x = 0.70 moles
3.- Divide by the lowest number of moles
Ag = 0.69/0.69 = 1
Cl = 0.70 / 0.69 = 1.02 ≈ 1
4.- Write the empirical formula
Ag₁ Cl₁ = AgCl
The percent by mass of 110.6 g of potassium fluoride (NaF) dissolved in 1500.0 g of water is 0.073733 %.
<h3>
What is the mass percentage?</h3>
The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.
Calculate the mass percent of potassium fluoride, using the formula:
Mass percentage = 0.073733 %
Hence, the percent by mass of 110.6 g of potassium fluoride (NaF) dissolved in 1500.0 g of water is 0.073733 %.
Learn more about the mass percentage here;
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Answer:
Neutralization.
Explanation:
"In chemistry, neutralization is a chemical reaction in which an acid and a base react quantitatively with each other."
The neutralization reaction is:
Ca(OH)2 + 2HBr ---------- CaBr2 + 2H2O
Therefore based on the reaction stoichiometry, the ratio of Ca(OH)2 : HBr = 1:2
Titration data:
Concentration of HBr = 5.00 *10^-2 M
Volume of HBr required = 48.8 ml = 0.0488 L
# moles of HBr = 5.00 *10^-2 moles L-1 * 0.0488 L = 0.00244 moles
Based on the reaction stoichiometry:
Moles of Ca(OH)2 = 1/2 * Moles of HBr = 1/2 * 0.00244 = 0.00122 moles
Volume of Ca(OH)2 taken = 100 ml = 0.1 L
Concentration of Ca(OH)2 = 0.00122/0.1
= 0.0122 M = 1.22 * 10^-2 M
