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2 years ago

Calculate the Molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution.

Chemistry

1 answer:

Nana76 [90]2 years ago

5 0

The molarity is 0.151 mol/L
Hope it helps.

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How is hydrogen in heavy water different from hydrogen in normal water?

I am Lyosha [343]

Answer:C

Explanation:Apex

6 0

3 years ago

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Write the pair sequence using the right base for the mouse DNA. ATGGGTGATGTTGAAAAAGGCAAGAAGATTTTTGTTCAGAAGTGTGCCCAGTGCCACACT

inysia [295]

Answer:

Explanation:

Every A will be paired with a T, and every C with a G and vice versa (T to A, and G to C)

So the first letters in the sequence are ATGGG. So the pair will be TACCC.

4 0

2 years ago

1) a solution with a hyrdrogen ion concentration of 1x10^-4 moles/liter would have a PH of what?

lana66690 [7]

Answer:

pH = -log(concentration of hydro.gen ion)

1. When con. of H ion is 1*10-4 mol/L

pH = -log(1*10-4) = -(-4) = 4

2. A solution with a pH of 1*10-12mol/L

pH = -log (1*10-12) = -(-12) = 12

The pH is 12 and the solution is basic or alkaline

3.A solution with a pH of 6 has the concentration of

pH = -log (H+)

(H+) = arc log -pH

(H+) = 1*10-6

Explanation:

7 0

2 years ago

5. The element copper has naturally occurring isotopes with mass numbers of 63

natali 33 [55]

Answer:

63.616

Explanation:

DATA

1. first atomic mass;m1=63

second atomic mass;m2=65
first percentage;p1= 69.2%
second percentage me;p2=30.8%
average mass;avg= ?

SOLUTION

avg= (m1)(p1) + (m2)(p2)

100

avg= (63)(69.2) + (65)(30.8)

100

avg= 4359.6 + 2002

100

avg= 6361.6

100

avg= 63.616

4 0

2 years ago

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Calculate the no. of each atoms presents in 10 grams of calcium carbonate.

raketka [301]

Molar Mass of Calcium carbonate:-

$\\ \sf\longmapsto CaCO_3$

$\\ \sf\longmapsto 40u+12u+3(16u)$

$\\ \sf\longmapsto 52u+48u$

$\\ \sf\longmapsto 100u$

$\\ \sf\longmapsto 100g/mol$

Given Mass=10g

$\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}$

$\\ \sf\longmapsto No\:of\;moles=\dfrac{10}{100}$

$\\ \sf\longmapsto No\:of\:moles=0.1mol$

Now

$\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}$

$\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 6.023\times 10^{22}molecules$

8 0

2 years ago