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ss7ja [257]
3 years ago
5

Okay so we have this question of the week thing and this week our answer is 8 so i need a algebra problem that is a two step equ

ation and equals 8 can someone please help me ?
Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

2x+4=8

x=2

2 times 2 equals 4

Four plus four is 8

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Solve plz<br> 500 - 2.23
Strike441 [17]

Answer:

497.8

Step-by-step explanation:

500-2.23=497.77=497.8

7 0
2 years ago
Read 2 more answers
Find the measure of each angle indicated.
Ivanshal [37]

Answer:

3) B) 90°

4) A) 75°

Step-by-step explanation:

3) interior angles of a triangle =180°

So

40+50+?=180

? =180- 90

? =90

4) same rule

40+65+?=180

? =180 - 105

? = 75

8 0
2 years ago
Solve the proportion:
Sav [38]

Answer:

Cross multiply

6k+18=150

6k= 132

k=132/6

k=23.66

4 0
2 years ago
I don’t understand this can someone please give me and example on how to do it please?
olga55 [171]
For the first one,

you multiply 5x and -5 to get -25.

Then you move the constant to the right and change the sign to get 3x= -21 +25.

Calculate the sum of -21+25 to get 4.

Divide both sides of the equation by 3 to get x=4/3.

So then your final answer is x=4
——
3


For the second one,

Distribute 7 through the parentheses to get 14x + 14+8=120

The you add 14+8 to get 22. Your equation should be 14x+22=120

Move the constant to the right side and change its sign to get 14x=120-22

Subtract 120-22 to get 98. Now your equation should be 14x=98

Divide both sides of the equation by 14 to get x=7.

Your finial answer for the second one should be x=7.
—————————————————————-
I hope this made sense.
5 0
2 years ago
Please find the square roots of the following complex number.
Nana76 [90]

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

6 0
2 years ago
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