1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ira [324]
3 years ago
9

Whats the ratio of KMnO4:KCl =

Chemistry
1 answer:
Natasha2012 [34]3 years ago
5 0
(K+ + MnO4- )+(K+ +Cl- )
This would be a one to one ratio as the charges of each component are equal 
You might be interested in
When CO2 decomposes into oxygen and carbon, it gives a gram ratio of 2.67:1 O2:C. When a 32.4g of CO2 decomposes, how many grams
Rufina [12.5K]

Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

CO_2\rightarrow O_2+C

As we are given:

\text{Mass of }O_2}:\text{Mass of }C=2.67:1{

According to the law of conservation of mass,

Total mass of CO_2 = Mass of O_2 + Mass of C

Total mass of CO_2 = 2.67 + 1 = 3.67 g

Now we have to calculate the mass of O_2 and C.

\text{Mass of }O_2=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }O_2=\frac{32.4g}{3.67g}\times 2.67=23.6g

and,

\text{Mass of }C=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }C=\frac{32.4g}{3.67g}\times 1=8.83g

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

6 0
3 years ago
Miss White wants to make a (decidedly not poisoned) apple pie. The recipe she is
Rina8888 [55]
So you have to multiply 786,3 times 0.98 to get the mass the mass is 770.57 if u round its 770.6 or 771
5 0
3 years ago
What activates a convenient current starting to flow of a fluid?
Lostsunrise [7]

hlo guys you are so bads i

3 0
1 year ago
How many moles are their in 62.0 grams of CO2
Advocard [28]
6.2 grams of CO2 = 1.408786739226764 moles
6 0
2 years ago
Read 2 more answers
Two different atoms have four protons each and the same mass. However, one has a positive charge while the other is neutral. Des
seraphim [82]

The possible number and location of all subatomic are one of them is electrically neutral, while the other has a stable electronic configuration.

<h3>What are subatomic particles?</h3>

Subatomic particles are those particles that are present inside the atoms. They are electron, neutron, and proton. They are charged particles, protons are positively charged, electrons are negatively charged and neutrons are neutral.

The protons and electrons totally contribute to the atomic mass of the elements.

Thus, the subatomic particles are electrically neutral and stable to electronic configurations.

To learn more about subatomic particles, refer to the below link:

brainly.com/question/13303285

#SPJ1

8 0
1 year ago
Other questions:
  • What moves across axons?
    5·2 answers
  • A covalent chemical bonds in which_____.
    15·1 answer
  • If you crashed your car into a house, which kind of insurance would you use: a) Homeowners insurance b) Renters insurance c) Dis
    12·1 answer
  • Find the initial temperature of Aluminum if 35 g of it produces 781.2 Joules at the final temperature of 44.3 ºC.
    7·1 answer
  • How does pollution affect air resources?
    10·1 answer
  • What are this element’s chemical and physical properties? Explain how the chemical properties affect the physical properties of
    8·1 answer
  • How are clouds formed? Simple answer please!
    13·2 answers
  • Please help with this question!
    7·2 answers
  • Calculate the [H+] for a solution with a pOH of 4.75
    10·1 answer
  • What is the net ionic equation for the reaction shown below?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!