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oksian1 [2.3K]
2 years ago
6

Determine the concern traction in [M] of a solution that has an absorbance of 0.420

Chemistry
1 answer:
ZanzabumX [31]2 years ago
8 0

The Concenteration of a solution that has an absorbance of 0.420

is 5.27 μМ

<h3> </h3><h3>What is Absorbance ?</h3>

Absorbance (A), also known as optical density (OD), is the quantity of light absorbed by a solution.

Transmittance is the quantity of light that passes through a solution.

We can measures the absorbance of a sample using a spectrophotometer and the value is A = 0.420.

We can calculate the concentration of the sample using the Beer-Lambert law, which relates the attenuation of light to the properties of the material through which the light is travelling, through the following equation.

A = ∈ x c x d

Where ;

  • A =  Absorbance
  • ∈ =  molar absorptivity of the species (7.96 × 10⁴ M⁻¹ cm⁻¹)
  • c  =  concentration
  • d = optical path length (1.00 cm)

Therefore,

c = A / ∈ x d

  = 0.420 / 7.96 × 10⁴ M⁻¹ cm⁻¹ x 1.00 cm  

  = 5.27 μМ

Learn more about spectrophotometer here ; brainly.com/question/20956841

#SPJ1

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Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

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The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

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