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Jlenok [28]
3 years ago
13

Will give Brainliest to the best answer! Please help ASAP!

Chemistry
1 answer:
vazorg [7]3 years ago
6 0
Calcium is less reactive then the others
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Determine the pH of a 0.188 M NH 3 solution at 25°C. The K b of NH 3 is 1.76 × 10 -5.
Archy [21]

Answer:

pH is 8.52

Explanation:

According to the working in the photo

5 0
3 years ago
What is a chemical property of soda ash
xz_007 [3.2K]
Soda  ash   which  is  also referred  to  as   sodium  carbonate with  a  chemical  formula (NaCO3)  has  the   following   chemical   formula
The   melting   point   of  851  degrees
The  molecular  weight  of  105.98
Its  density  at   25  degrees  is =2.53 g/cm^3
Its  specific  heat  capacity  at  25  degrees = 0.249  cal/gm/ 0c
4 0
4 years ago
An object traviling around another object in space is in
gogolik [260]

Answer:

I think this the asnwer a satellit

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8 0
3 years ago
Read 2 more answers
1. If I have 45 L of He in a balloon at 25 degrees celsius and increase the temperature of the
Greeley [361]

Use Charles' Law: V1/T1 = V2/T2. We assume the pressure and mass of the helium is constant. The units for temperature must be in Kelvin to use this equation (x °C = x + 273.15 K).

We want to solve for the new volume after the temperature is increased from 25 °C (298.15 K) to 55 °C (328.15 K). Since the volume and temperature of a gas at a constant pressure are directly proportional to each other, we should expect the new volume of the balloon to be greater than the initial 45 L.

Rearranging Charles' Law to solve for V2, we get V2 = V1T2/T1.  

(45 L)(328.15 K)/(298.15 K) = 49.5 ≈ 50 L (if we're considering sig figs).

7 0
3 years ago
Given: C + O2 → CO2 Bond Bond Energy (kJ/mol) C=O 799 O=O 494 Calculate the enthalpy change for the chemical reaction. The chang
aliya0001 [1]

Answer:

-1104 kJ/mol

Explanation:

The change in the enthalpy of a reaction is equal to the difference between: the sum of the enthalpy changes of the bonds broken and the sum of the enthalpy changes of the bonds formed.

The bonds broken correspond to the cleavage of bonds of the reactants, the bonds formed correspond to the bonds of the products:

  • we only break oxygen O=O bond, since carbon is not bonded to anything;
  • we form two C=O bonds in carbon dioxide.

Therefore, the enthalpy change is calculated by:

\Delta H^o = 1 mol\cdot 494 kJ/mol - 2 mol\cdot 799 kJ/mol = -1104 kJ/mol

3 0
3 years ago
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