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3 years ago

Which type of substance yields hydrogen ions h in an aqueous solution?

Chemistry

2 answers:

Bess [88]3 years ago

6 0

Acids dissociate in water to release a proton. The proton then combines with water to form a hydronium ion.

HCl, hydrochloric acid dissociates in water to release proton H⁺ and chloride ion Cl⁻

HCl → H⁺ + Cl⁻

H⁺ + H₂O → H₃O⁺

Blababa [14]3 years ago

5 0

Hydrogen-containing compounds that ionize to yield hydrogen ions (H+) in aqueous solution. Compounds that ionize to yield hydroxide ions (OH-) in aqueous solution.

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1 year ago

CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o

Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

$CO_{(g)}$ + $2H_2O_{(g)}$ ⇄ $CH_3OH_{(g)}$

The ICE table can be represented as:

$CO_{(g)}$ + $2H_2_{(g)}$ ⇄ $CH_3OH_{(g)}$

Initial 0.27 0.49 0.0

Change -x -2x x

Equilibrium 0.27 - x 0.49 -2x x

We can now say that the concentration of $CH_3OH_{(g)}$ at equilibrium is x;

Let's not forget that at equilibrium $CH_3OH_{(g)}$ = 0.11 M

So:

x = [ $CH_3OH_{(g)}$ ] = 0.11 M

[ $CO_{(g)}$ ] = 0.27 - x

[ $CO_{(g)}$ ] = 0.27 - 0.11

[ $CO_{(g)}$ ] = 0.16 M

[ $2H_2_{(g)}$ ] = (0.49 - 2x)

[ $2H_2_{(g)}$ ] = (0.49 - 2(0.11))

[ $2H_2_{(g)}$ ] = 0.49 - 0.22

[ $2H_2_{(g)}$ ] = 0.27 M

$K_C = \frac{[CH_3OH]}{[CO][H_2]^2}$

$K_C = \frac{(0.11)}{(0.16)[(0.27)^2}$

$K_C = 9.4307$

$K_C$ = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0

2 years ago

Someone pls help me I will mark you as brain

Reptile [31]

3rd one I think it is.

5 0

2 years ago

How many valence electrons are in the element copernicium? Will GIVE BRainLYEsT!!!!!

Ivahew [28]

As it is located at 7s ^2 it will have 2 valence electrons that due to its position in the s orbital it will be prone to losing them to obtain a noble gas configuration.

3 0

3 years ago

Read 2 more answers

Help please stuck and confused

Alecsey [184]

I’m pretty sure it’s none of the above cause I’m googling it a bunch and and it say you use the dideoxy method

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2 years ago