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3 years ago

An x- ray is part of the electromagnetic spectrum. Compared to photons of visible light, an x-ray has?

Physics

2 answers:

Julli [10]3 years ago

8 0

Explanation:

X-rays are the electromagnetic waves whose photons are of higher energy and short wavelength that ranges beyond the visible region for the human-eyes.

The visible light lies between the wavelength of 4000 $A^{\circ}$ to 7000 $A^{\circ}$ .

The x-ray photons are the result of highly excited electron from its ground state than the electron releasing visible light photons.

The smaller atoms, in which the electron orbitals are separated by relatively low jumps in energy, are less likely to absorb X-ray photons.

bezimeni [28]3 years ago

3 0

Explanation:

X-rays are almost same as the visible light as they both electromagnetic waves with same speed. However, the only difference the energy level of photons of X- rays are higher than those of the visible light. This is because the frequency of the X-rays are higher.

E= $h\nu$

h= plank's constant and \nu is the frequency of the wave. So, higher the frequency higher will be the energy of the wave.

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The generator at a power plant produces AC at 20,000 V. A transformer steps this up to 355,000 V for transmission over power lin

Masja [62]

Answer:

Number of coil in the output is 39938

Explanation:

We have given a step up transformer

Input voltage of transformer, that is primary voltage $v_p=20000volt$

Output voltage, that is secondary voltage $v_s=355000volt$

Number of turns in primary $N_p=2250$

For transformer we know that $\frac{V_p}{V_s}=\frac{N_p}{N_s}$

$\frac{20000}{355000}=\frac{2250}{N_s}$

$N_s=39937.5$

As the number of turns can not be in fraction so number of turns in the output coil is 39938

7 0

2 years ago

Just these 2 question. I have no idea what it's asking..

Murljashka [212]

Answer: did you get the answers?

Explanation:

5 0

2 years ago

In every trench over 4 feet (1.2 m) deep, there must be an exit every

ss7ja [257]

Explanation:

25 ft I believe that this is the best answer

5 0

2 years ago

WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain di

Yuki888 [10]

Answer:

$\lambda = 202.7 \ m$

$w = 9.3 *10^{6} \ rad/s$

$k = 0.031 m^{-1}$

$E_{max} = 9.0 *10^{-3} \ V/m$

Explanation:

From the question we are told that

The frequency of the radio station is $f= 1480 \ kHz = 1480 *10^{3}\ Hz$

The magnitude of the magnetic field is $B = 3.0* 10^{-11} \ T$

Generally the wavelength is mathematically represented as

$\lambda = \frac{c}{f}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

$\lambda = \frac{3.0 *10^{8}}{ 1480 *10^{3}}$

=> $\lambda = 202.7 \ m$

Generally the angular frequency is mathematically represented as

$w = 2 \pi * f$

=> $w = 2 * 3.142 * 1480 *10^{3}$

=> $w = 9.3 *10^{6} \ rad/s$

Generally the wave number is mathematically represented as

=> $k = \frac{2 \pi }{\lambda}$

=> $k = \frac{2 * 3.142 }{ 202.7}$

=> $k = 0.031 m^{-1}$

Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as

$E_{max} = c * B$

=> $E_{max} = 3.0 *10^{8} * 3.0* 10^{-11}$

=> $E_{max} = 9.0 *10^{-3} \ V/m$

3 0

2 years ago

A single conservative force acts on a 5.30-kg particle within a system due to its interaction with the rest of the system. The e

cupoosta [38]

Answer:

Given that

m = 5.3 kg

Fx = 2x + 4

We know that work done by force F given as

w= ∫ F. dx

Given that x=1.08 m to x=6.5 m

Fx = 2x + 4

w= ∫ F. dx

$w=\int_{1.08}^{6.5}(2x+4) .dx$

$w=\left [x^2+4x \right ]_{1.08}^{6.5}$

$w=(6.5^2-1.08^2)+4(6.5-1.08)\ J$

w=62.7 J

We know that potential energy given as

$F=-\dfrac{dU}{dx}$

∫ dU = -∫F.dx ( w= ∫ F. dx)

ΔU= -62.7 J

We know that form work power energy theorem

Net work = Change in kinetic energy

W= KE₂ - KE₁

62.7 =KE₂ - (1/2)x 5.3 x 3²

KE₂ = 86.55 J

This is the kinetic energy at 6.5m

8 0

2 years ago