Answer:
d is greater than c, since at ![x = 0, g(x) > f(x)](https://tex.z-dn.net/?f=x%20%3D%200%2C%20g%28x%29%20%3E%20f%28x%29)
Step-by-step explanation:
We are given two exponential functions, f and g.
Since f has the higher base(3 instead of 2 in g), it increases faster, so initially, g is greater than f, and after point (p,q), f is greater than g.
The values of c and d are found when
. At this point, we have that g is greater than f, so d is greater than c.
The first bag would be 5.34$ and the second would be 5.53$ and the second bag is better cause your only spending 19 more cents for 1.5 more pounds
Answer:
1/24
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Sajia can sell 21 books she can sell if she comes back on sunday and the required inequality is ![9 + x \leq 30](https://tex.z-dn.net/?f=9%20%2B%20x%20%5Cleq%2030)
<em><u>Solution:</u></em>
Given that Sajia has 30 Books in her library
She sold 9 books at the thrift store on Saturday
To find: We have to write and solve an inequality to determine number of more books she can sell if she comes back on sunday
Let "x" be the number of more books she can sell if she comes back on sunday
<em><u>We can write a inequality as:</u></em>
![\text{ books already sold } + \text{ number of books remaining } \leq \text{ total number of books she has }](https://tex.z-dn.net/?f=%5Ctext%7B%20books%20already%20sold%20%7D%20%2B%20%5Ctext%7B%20number%20of%20books%20remaining%20%7D%20%5Cleq%20%5Ctext%7B%20total%20number%20of%20books%20she%20has%20%7D)
![9 + x \leq 30](https://tex.z-dn.net/?f=9%20%2B%20x%20%5Cleq%2030)
Now moving 9 from L.H.S to R.H.S we get,
![x \leq 30 - 9](https://tex.z-dn.net/?f=x%20%5Cleq%2030%20-%209)
On solving 30 - 9 = 21,
![x \leq 21](https://tex.z-dn.net/?f=x%20%5Cleq%2021)
So Sajia can sell 21 books she can sell if she comes back on sunday