The experimental mole ratio of silver chloride to barium chloride is calculated as below
fin the mole of each compound
mole= mass/molar mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102 moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol = 0.049 moles of BaCl2
find the mole ratio by dividing each mole with the smallest mole(0.049)
AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore the mole ratio AgCl to BaCl2 is 2 :1
Answer: C
Explanation: Took the test
The combined gas law combines the three gas laws: Boyle's Law, Charles'Law, and Gay-Lussac's Law. It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant. When Avogadro's law is added to the combined gas law, the ideal gas law res
Answer is volume and pressure only
For one a homogenous mixture cannot be separated using filtration. Hope this helps:)
Answer:
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 
Explanation:
From the question we are told that
The number of moles of is 
The formation reaction of
is
From the reaction we see that
1 mole of
is formed by 2 moles of
1 mole of
and 4 
This implies that
4.90 moles of
will produce (2 * 4.90) moles of
,
(1 * 4.90) moles of
and
(8 * 4.90) moles of 
So
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 