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r-ruslan [8.4K]
3 years ago
10

Distinguish between dunes and loess

Chemistry
1 answer:
agasfer [191]3 years ago
6 0

Answer:

Dunes are loose sand hills.

Loess is a compacted wind-blown formation of sediment.

Explanation:

Sand dunes are, as their name implies, made of sand which is itself made of tiny quartz pieces. Sand dunes are present where there is a ready source of broken down sandstone or other type of rock and wind to transport the sand. The dunes are mobile and loose and migrate over time.

Loess comes in vast formations and was created in a very different way. In the last ice age, winds from the north carried sediments loosened and ground by glaciers southwards. There, the sediments accumulated in large formations and became compacted over time.

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Which term describes a substance that increases the concentration of hydroxide (OH-) ions in solution? *
saul85 [17]

Answer:

The correct answer to the following question will be "Arrhenius base".

Explanation:

  • An Arrhenius base seems to be a material that raises the ion concentration (hydroxide) when exposed to water and thereby reduces the concentration of ions (hydronium).
  • This acid, as well as base model, claims an acid is indeed a material that incorporates hydrogen or ionizes protons throughout aqueous, while a base would be a material that comprises hydroxide while releases everything in a that solution

So that the above is the right answer.

8 0
3 years ago
Read 2 more answers
If 100. ml of water is added to 25 ml of 5.0 m nacl, the final concentration is __________.
Iteru [2.4K]
We may apply a mass balance here. The total moles of NaCl will remain constant before and after the mixing of the solutions. We have three solutions:
1) 25 ml of 5 M NaCl
2) 100 ml of 0 M NaCl
3) A mixture of these solutions with volume 125 ml and concentration C

The moles of a substance are equal to the product of the concentration and volume. Thus:

25 * 5 + 100 * 0 = 125 * C
C = 1 M

The concentration of the final solution is 1 M.
4 0
3 years ago
Read 2 more answers
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
3 years ago
The feed to a batch process contains equimolar quantities of nitrogen and methane. write an expression for the kilograms of nitr
timama [110]
1) number of moles of N2 = n/2

2) Number of moles of CH4 = n/2

3) Total number of moles of the mixture = n/2 + n/2 = n

4) Kg of N2

mass in grams = number of moles * molar mass

molar mass of N2 = 2 * 14.0 g/mol = 28 g/mol

=> mass of N2 in grams = (n/2) * 28 = 14n

mass of N2 in Kg = mass of N2 in grams * [1 kg / 1000g] = 14n/1000 kg = 0.014n kg

Answer: mass of N2 in kg = 0.014n kg
3 0
3 years ago
Chemistry help. Will give Brainliest!
VashaNatasha [74]
#1. An element or ion that has lost two electrons must have a net charge of 2+, because it has two more protons than electrons, therefore the answer is Mg2+

#2. aluminum ions have an oxidation state of 3+ and fluoride has an oxidation state of 1-, therefore I’m order for the charges to cancel you need 3 fluoride ions.
Therefore, the answer is AlF3
8 0
3 years ago
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