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ruslelena [56]
3 years ago
10

Which compound could be added to hydroiodic acid to neutralize its acidic properties ?

Chemistry
2 answers:
netineya [11]3 years ago
6 0

methylamine, a weak base.

Juli2301 [7.4K]3 years ago
5 0

A base could be added so anything with a hydroxide or oxide group

E.g NaOH

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While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
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What best describes ionization energy?
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Answer: energy needed to remove an electron from an atom or ion in the gas phase. Explanation: That is the very definition of ionization energy: ionization energy is the energy needed to remove (get appart) an electron from a neutral atom or ion in gas phase.Jun 19, 2016


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What is the significance of wanting to know what the pH of a solution is?
balu736 [363]

pH is an important parameter for many reactions to take place in solution and in biological systems. It is related to the concentration of H⁺ ions through the following expression:

pH = 1/[H⁺] = -log [H⁺]

Wanting to know the pH of a solution is equivalent to knowing the amount of hydrogen ions present. But the pH scale is more convenient than the concentration scale because pH usually takes values between 0 and 14.

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4 0
3 years ago
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
3 years ago
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