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mel-nik [20]
3 years ago
13

Use the distributive property to expand the following expression. (9m - 6)7

Computers and Technology
2 answers:
Nady [450]3 years ago
7 0
(9m - 6)7
(9m × 7) - (6 × 7)
63m - 42
taurus [48]3 years ago
7 0

Answer:

After expansion result will be  63m - 42

Explanation:

We have given equation (9m-6)7

We have to expand this using the distributive property

In distributive property we have to do separate calculations

So first multiply 9m to 7 result will be 63 m

Now multiply -6 to 7 result will be -42

Now combine the results of both the operations = 63m - 42

So the result after expansion from distributive property will be  63m - 42

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Record

Explanation:

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Eli has 7 games on his phone. His sister has 6 more than him. Which ratio compares the number of games on Eli’s phone to the num
Ulleksa [173]

Answer:

7:13

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First figure out how many his sister has so 6+7=13 so the ratio is 7:13 because of how its worded since it says Eli's games first then thats how you get 7 then his sisters 13 so final answer 7:13 There is you answer

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1 year ago
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Given two character strings s1 and s2. Write a Pthread program to find out the number of substrings, in string s1, that is exact
anyanavicka [17]

Answer:

Explanation:

#include <stdlib.h>

#include <stdio.h>

#include <string.h>

#define MAX 1024

int total = 0 ;

int n1, n2;

char s1, s2;

FILE fp;

int readf(FILE fp)

{

 if((fp=fopen("strings.txt", "r"))==NULL) {

   printf("ERROR: can’t open string.txt!\n");

   return 0;

 }

 s1=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 s2=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 /* read s1 s2 from the file */

 s1=fgets(s1, MAX, fp);

 s2=fgets(s2, MAX, fp);

 n1=strlen(s1); /* length of s1 */

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}

int num_substring(void)

{

 int i, j, k;

 int count;

 for(i=0; i<=(n1-n2); i++) {

   count=0;

   for(j=i, k=0; k<n2; j++, k++){ /* search for the next string of size of n2 */

   if((s1+j)!=(s2+k)) {

     break;

   }

   else

     count++;

   if(count==n2)

     total++; /* find a substring in this step */

   }

 }

 return total;

}

int main(int argc, char argv[])

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3 0
3 years ago
Holly needs to create an online survey to find out what people want and is
Dahasolnce [82]

Answer:

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Answer

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The second, an else if statement;

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