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Katarina [22]
3 years ago
15

Please Help Why is laboratory safety important? Describe a scenario illustrating your reason(s).

Chemistry
1 answer:
Virty [35]3 years ago
3 0
So that you can learn while being safe. Wearing goggles, for eye protection when dealing with chemicals
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5. What is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm?
Helga [31]

70.33 L  is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm.

<h3>What is volume?</h3>

Volume is the percentage of a liquid, solid, or gas's three-dimensional space that it occupies.

Liters, cubic metres, gallons, millilitres, teaspoons, and ounces are some of the more popular units used to express volume, though there are many others.

We will use ideal gas law to find the volume

PV = nRT

Can also be written as

V = (nRT)/P

Where,

P = pressure

V = volume

n = amount of substance

R = ideal gas constant

T = temperature

Here, we have given

P = 3.5 atm

V = to find

n = 10 moles

R = 0.08206 L⋅atm/K⋅mol

T = 300k

Lets substitute the values

V = (10 × 0.08206 × 300)/3.5

V =  70.33 L

Learn more about volume

brainly.com/question/463363

#SPJ10

3 0
1 year ago
0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ? How many digits to the right of the decimal point should be used to report the resu
ki77a [65]

Consider the following equation:0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g  = ? How many digits to the right of the decimal point should be used to report the result? =2, Choose the correct answer=9.66 × 10^-3 g, Which metric unit would be the best choice to report the result?=mg

4 0
3 years ago
Read 2 more answers
Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G
seraphim [82]

<u>Answer:</u> The mass of sodium chloride solution present is 0.256 grams.

<u>Explanation:</u>

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g     (Conversion factor:  1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = \frac{100}{39}\times 0.1=0.256g of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

8 0
3 years ago
Which represents potential energy? A)bread baking B)lawnmower cutting grass C)car racing downhill D)weed whacker full of gas
Marizza181 [45]
Potential energy is the energy stored. What do u think it is? (I don't really know)
5 0
4 years ago
Read 2 more answers
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
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