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2 years ago

How many moles are present in 2.7 liters of Argon gas at STP?

Chemistry

1 answer:

Neko [114]2 years ago

4 0

6.9 cause argon is a proactive system that can be sick

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If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff

sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , $F=\mu_kN$ ( here $\mu_k$ is coefficient of kinetic friction and N is normal force)

Therefore, $\mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k$

Now, both forces are equal.

$122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26$

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0

3 years ago

Soil texture is based on?

blsea [12.9K]

It is based on the water underground

3 0

3 years ago

Which electrons are lost by an atom of iron when it forms the Fe3+ ion?

astra-53 [7]

The two s Orbital electrons and one d orbital electron, are the electrons that are lost by an atom of Iron when it forms the Fe3 + ion.

8 0

3 years ago

Read 2 more answers

To determine the freezing point depression of a LiCl solution, Toni adds 0.411 g of LiCl to the sample test tube along with 19.7

Cerrena [4.2K]

Answer:

LiCl = 0.492 m

Explanation:

Molal concentration is the one that indicates the moles of solute that are contained in 1kg of solvent.

Our solute is lithium chloride, LiCl.

Our solvent is distilled water.

We do not have the mass of water, but we know the volume, so we should apply density to determine mass.

Density = mass / volume

Density . volume = mass

1 g/mL . 19.7 mL = 19.7 g

We convert g to kg → 19.7 g . 1 kg / 1000g = 0.0197 kg

Let's determine the moles of LiCl

0.411 g . 1 mol / 42.394 g = 9.69×10⁻³ moles

Molal concentration (m) = 9.69×10⁻³ mol / 0.0197 kg → 0.492 m

7 0

2 years ago

What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]

valentinak56 [21]

Answer: The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

${\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%$

Given: mass of sulphur = 32 g/mol

mass of $Al_2(SO_4)_3$ = 342 g/mol

Putting in the values we get:

${\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%$

The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

4 0

3 years ago