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Lostsunrise [7]
2 years ago
12

How many moles are present in 2.7 liters of Argon gas at STP?

Chemistry
1 answer:
Neko [114]2 years ago
4 0

6.9 cause argon is a proactive system that can be sick

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Hitman42 [59]

Answer:

x=2.8moles

Explanation:

first step balance the chemical equation

C2H6+O2-->CO2+2H2O

use more ratio to find the moles of water

1mole of C2H6= 2 moles of H2O

1.4mole of C2H6=?x

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x=2.8 moles of H2O

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3 years ago
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

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gizmo_the_mogwai [7]
Possibly decomposition but not sure
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3 years ago
Read 2 more answers
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