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liraira [26]
3 years ago
5

Draw the lewis dot structures for each of the following molecules. show the resonance structures, if they exist

Chemistry
1 answer:
jonny [76]3 years ago
5 0
What dont u understand about lewis dot structures???.
.how to determine the number of dots ..or
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When n = 4, l = 2, and ml = -1, to what orbital type does this refer?
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will tell you the subshell type, so you are dealing with a d orbital.  

ml will tell you the orientation of the orbital, there is no distinction between the orbitals so -1 doesnt specifically mean anything.

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How water deposits soil sediment and rock
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Be sure to answer all parts. For the complete redox reactions given here, write the half-reactions and identify the oxidizing an
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Answer : O_2 is the oxidizing agent and Fe is the reducing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

4Fe+3O_2\rightarrow 2Fe_2O_3

The half oxidation-reduction reactions are:

Oxidation reaction : Fe\rightarrow Fe^{3+}+3e^-

Reduction reaction : O_2+4e^-\rightarrow 2O^{2-}

In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.

Oxidation reaction : 4Fe\rightarrow 4Fe^{3+}+12e^-

Reduction reaction : 3O_2+12e^-\rightarrow 6O^{2-}

4Fe+3O_2\rightarrow 2Fe_2O_3

In this reaction, 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'O_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, O_2 is the oxidizing agent and Fe is the reducing agent.

7 0
3 years ago
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