Answer:
Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:
Where is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:
Also, at sea level, we have an atmospheric pressure of:
Given mole fraction:
According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:
Then the equation becomes:
Solve for :
Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:
Apply Henry's law using the constant we found:
Answer: C4H
Explanation:
An hydrocarbon is a compound with carbon and hydrogen atoms only covalently linked together.
Thus, all hydrocarbons have a basic formula of CH.
Now, mass of hydrocarbon = 100%
Mass of hydrogen = 20%
Mass of carbon = (100% - 20%) = 80%
i.e Carbon : Hydrogen
= 80% : 20%
= (80% / 20%)
= 4 : 1
Thus, the empirical formula of the hydrocarbon is C4H
Answer:
The answer is 2Fe(No3)3 + 3Na2CO3 -> Fe2(CO3)3 + 6NaNO3 .
Explanation:
Fe(lll) represents <em>I</em><em>r</em><em>o</em><em>n</em><em> </em><em>(</em><em>l</em><em>l</em><em>l</em><em>)</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em> </em><em>.</em>
NO3 represents<em> </em><em>N</em><em>i</em><em>t</em><em>r</em><em>a</em><em>t</em><em>e</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em> </em><em>.</em>
Na represents<em> </em><em>S</em><em>o</em><em>d</em><em>i</em><em>u</em><em>m</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em> </em><em>.</em>
CO3 represents<em> </em><em>C</em><em>a</em><em>r</em><em>b</em><em>o</em><em>n</em><em>a</em><em>t</em><em>e</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em>.</em>
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