1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gelneren [198K]
3 years ago
8

When HBr combines with water, it produces H3O+ and Br- ions. This shows that HBr is a base. true false

Chemistry
2 answers:
ELEN [110]3 years ago
6 0
HBr is a strong acid

False
masha68 [24]3 years ago
6 0

Answer:

The given statement is false.

Explanation:

Hydrogen bromide when dissolves in water it gives hydronium ions and bromide ions.The hydronium ions is due to association of hydrogen ion with water molecule.This means that hydrogen bromide is an acid.

HBr+H_2O\rightarrow H_3O^++Br^-

Where as bases are those compounds which free hydroxide ion sin their aqueous solutions.

BOH\rightarrow B^++OH^

So, from this we concluded that HBr is not a base but an acid.

You might be interested in
Which of the following is not a possible termination step in the free radical chlorination of methane? Group of answer choices ∙
vagabundo [1.1K]

Answer: first option is not a termination

∙CH3 + Cl2 → CH3Cl + Cl∙

Explanation:

Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product

7 0
3 years ago
How many grams of Kr are in a 9.59 L cylinder at 46.0 'C and 4.62 atm?<br> mass:
Sladkaya [172]

Answer:

Mass = 141.6 g

Explanation:

Given data:

Mass of Kr in gram =  ?

Volume in L = 9.59 L

Temperature = 46.0°C

Pressure = 4.62 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

46.0+273 = 319 K

4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K  ×319 K

44.3 atm.L = n×26.19 atm.L/ mol

n = 44.3 atm.L / 26.19 atm.L/ mol

n = 1.69 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1.69 mol × 83.79 g/mol

Mass = 141.6 g

8 0
3 years ago
Your theoretical yield is 81.2 grams, and your actual yield is 78.2 grams. What is the percent yield?
ioda

Answer:

66.2

Explanation:

3 0
3 years ago
Use the following equation to answer the questions below.
sertanlavr [38]

Answer:

Explanation:

Here is ur answer what you wanna do first is calculate the first and second numbers and letters this should be ur answer = -394 + 2 x (-242) - (-75) + 2 x 0 = -803 kJ/mol

4 0
3 years ago
Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO. Fe2O3 + 3CO --&gt; 2Fe + 3CO2 In the process, 213
s344n2d4d5 [400]
To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams. 
8 0
3 years ago
Other questions:
  • What type(s) of intermolecular forces are expected between seh2 molecules?
    10·2 answers
  • What part of the water is affected by a wave in deep water
    5·2 answers
  • Temperature is a measure of
    12·2 answers
  • A catalyst is a chemical:
    10·2 answers
  • Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
    7·1 answer
  • Which equation represents neutralization?
    6·1 answer
  • What do we mean when we say atoms bond together?
    7·1 answer
  • How many moles of KBr are present in 1000 ml of a 0.02 M KBr solution?
    6·1 answer
  • what happens when the gas produced by heating chloroform with silver powder is passed into Ammoniacal silver nitrate solution​
    9·2 answers
  • Porque a las vacunas los cientificos los llaman reactivos.​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!