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zheka24 [161]
3 years ago
11

Explain the concepts o f polymorphism, Encapsulation, Inheritance in detail with suitable examples?

Computers and Technology
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Encapsulation:-It is the binding of the data and functions so that they works as one unit.

Inheritance:-When one class acquires the property of another class it is called inheritance.

Polymorphism :-It generally means more than one form

Explanation:

Encapsulation:- class is an example of encapsulation it can hold different data types and functions in a single container called class.

class Name{

public:

string first_name;

string last_name;

void Display()

{

cout<<first_name<<" "<<last_name<<endl;

}

};

Inheritance:-The property of a class acquiring the properties of another class is called inheritance.

Now we will inherit the above defined class.

class person: public Name

{

public:

char gender;

int age;

void Display()

{

cout<<first_name<<" "<<last_name<<gender<<age<<endl;

}

};

int main()

{

Name n;

person p;

n.Display();

p.Display();

}

Polymorphism- There are two types of polymorphism:-

1.Run time polymorphism=The values are decided at run time.

2.Compile time polymorphism=The values are decided at compile time.

Example:-In the above example we have function Display() in both the classes.This is an example of compile-time polymorphism. We are deciding at the time of compilation which display to use.

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Explanation:

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2 years ago
The three basic processes of memory are ______.
marysya [2.9K]

Answer:

The correct answer is letter "C": encoding, storage, retrieval.

Explanation:

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3 years ago
Consider the following language:
VMariaS [17]

L is a decidable language because the Turing machine accepts it.

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<h3>How do you know if a language is decidable?</h3>

A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,

Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.

So,  L is a decidable language because the Turing machine accepts it.

L is a recognizable language if  TM M recognizes it.

Learn more about programming language from

brainly.com/question/16936315

#SPJ1

8 0
1 year ago
Using Karnaugh maps, simplify the following Boolean function:
Flura [38]

Answer:

F(a,b,c,d)=b'c' + a'cd' + ab'd'.

Explanation:

The image of the corresponding k-map is attached to this answer please refer it.By the sop given in the question the k-map is formed.There are 3 groups formed 1 group of four 1's and 2 groups of 2 1's.Hence there are three sop and the sop is reduced from the previous SOP.

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3 years ago
A(n) _____ chart is drawn on the same worksheet as the data.
Harrizon [31]
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