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2 years ago

Write the complete word equation for the combustion of methane (CH4(g))

Chemistry

1 answer:

Vlad [161]2 years ago

3 0

Answer:

See the explanation.

Explanation:

$CH_{4 } + O_{2} ------> CO_{2} + 2H_{2 } O$

Hydrocarbons on combustion give carbon dioxide and water.

Hydrocarbons contain all kinds of saturated and unsaturated ones.

Alkanes on reaction with oxygen gives carbon dioxide and water.

Alkenes on reaction with oxygen gives carbon dioxide and water.

Alkynes on reaction with oxygen gives carbon dioxide and water.

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How many molecules are there in 8.25 moles of CaHia?

expeople1 [14]

The number of molecules : 4.967 x 10²⁴

<h3>Further explanation </h3>

A mole is a number of particles(atoms, molecules, ions) in a substance

This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

8.25 moles of C₈H₁₈

The number of molecules :

$\tt 8.25\times 6.02\times 10^{23}=4.967\times 10^{24}$

8 0

2 years ago

The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa

Margarita [4]

Answer:

$\boxed{\text{1.81 da}}$

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

$\ln\dfrac{A_{0}}{A_{t}} = kt$

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

$\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}$

The half-life for decay is $\boxed{\textbf{1.81 da}}$ .

3 0

3 years ago

What is the surface area of the given figure?

eduard

Answer:

the answer will be 2,280 cm>2

3 0

2 years ago

2a. Write down the names of the new substances formed when each of the following substance reacts with dilute hydrochloric acid.

Naddika [18.5K]

Answer:

i) Dilute hydrochloric acid will react with Ammonia to form ammonia salt.

ii) dilute hydrochloric acid will react with soduim hydroxide to form sodium chloride and water

iii) dilute hydrochloric acid will react with calcuim carbonate to form Calcium chloride, Carbon dioxide and water.

Explanation:

CHEMICAL EQUATIONS :

I) HCL + NH3 = NH4Cl

ii) HCL+ NaOH = NaCl + H2O

iii) HCL + CaCo = CaCl2 + CO2 + H2O

7 0

2 years ago

Read 2 more answers

Calculate the concentration of all species in a 0.160 m solution of h2co3.

enot [183]

H₂CO₃ ⇔ HCO₃⁻ + H⁺

I 0.160 0 0

C -x +x +x

E 0.160-x +x +x

Ka1 = [HCO₃⁻][H⁺] / [H₂CO₃]

4.3 x 10⁻⁷ = x² / (0.160-x) (x is neglected in 0.160-x = 0.160)

x² = 6.88 x 10⁻⁸

x = 2.62 x 10⁻⁴

HCO₃⁻ ⇔ CO₃⁻² + H⁺

I 2.62 x 10⁻⁴ 0 2.62 x 10⁻⁴

C -x +x +x

E 2.62 x 10⁻⁴ - x +x 2.62 x 10⁻⁴ + x

Ka2 = [CO₃⁻²][H⁺] / [HCO₃⁻]

5.6 x 10⁻¹¹ = x(2.62 x 10⁻⁴ + x) / (2.62 x 10⁻⁴ - x)

x = 5.6 x 10⁻¹¹

Thus,

[H₂CO₃] = 0.160 - (2.62 x 10⁻⁴) = 0.16 M

[HCO₃⁻] = 2.62 x 10⁻⁴ - ( 5.6 x 10⁻¹¹) = 2.6 x 10⁻⁴ M

[CO₃⁻²] = 5.6 x 10⁻¹¹ M

[H₃O⁺] = 2.62 x 10⁻⁴ + 5.6 x 10⁻¹¹ = 2.6 x 10⁻⁴ M

[OH⁻] = 3.8 x 10⁻¹¹

8 0

2 years ago