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2 years ago

Write the complete word equation for the combustion of methane (CH4(g))

Chemistry

1 answer:

Vlad [161]2 years ago

3 0

Answer:

See the explanation.

Explanation:

$CH_{4 } + O_{2} ------> CO_{2} + 2H_{2 } O$

Hydrocarbons on combustion give carbon dioxide and water.

Hydrocarbons contain all kinds of saturated and unsaturated ones.

Alkanes on reaction with oxygen gives carbon dioxide and water.

Alkenes on reaction with oxygen gives carbon dioxide and water.

Alkynes on reaction with oxygen gives carbon dioxide and water.

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A teacher uses a bow and arrow to demonstrate accuracy and precision. She shoots several arrows, aiming at the exact center of t

RUDIKE [14]

Answer:Doing your momveryhardrn

Explanation:

She is visciously suckingmynuts

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2 years ago

g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol

Ronch [10]

Answer:

$M=0.0637M$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$Pb(NO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaNO_3(aq)$

Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

$n_{Pb^{2+}}=0.904gPbI_2*\frac{1molPbI_2}{461gPbI_2}*\frac{1molPb(NO_3)_2}{1molPbI_2} *\frac{1molPb^{2+}}{1molPb(NO_3)_2} =1.96x10^{-3}molPb^{2+}$

Finally, the resulting molarity in 30.8 mL (0.0308 L):

$M=\frac{1.96x10^{-3}molPb^{2+}}{0.0308L}\\ \\M=0.0637M$

Regards.

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2 years ago

How many atoms are in a sample of 0.75 moles of carbon atoms

vova2212 [387]

Answer: 4.5165 *10^-23 moles Carbon

Explanation:

There are 6.022*10^23 atoms in a mole.

Therefore, there would be 6.022*10^-23*0.75 atoms in 0.75 moles of Carbon.

= 4.5165 *10^-23 moles Carbon

8 0

2 years ago

Read 2 more answers

What is the electronic configuration for K2Cr2O7

dybincka [34]

Answer:

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1 year ago

The result of one experiment carried out by a research team would be considered valid if

Kaylis [27]

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2 years ago