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uranmaximum [27]
3 years ago
14

Write the complete word equation for the combustion of methane (CH4(g))

Chemistry
1 answer:
Vlad [161]3 years ago
3 0

Answer:

See the explanation.

Explanation:

CH_{4 }  + O_{2}  ------>  CO_{2}  + 2H_{2 } O

Hydrocarbons on combustion give carbon dioxide and water.

Hydrocarbons contain all kinds of saturated and unsaturated ones.

Alkanes on reaction with oxygen gives carbon dioxide and water.

Alkenes on reaction with oxygen gives carbon dioxide and water.

Alkynes on reaction with oxygen gives carbon dioxide and water.

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PLEASE I NEED HELP NOW!!! I WILL GIVE 25 POINTS
padilas [110]
If I did this correctly the balanced equation would be:
14H⁺+Cr₂O₇²⁻+6I⁻→3I₂+2Cr³⁺+7H₂O

oxidation half: (iodide was oxidized)
2I⁻→I₂+2e⁻

reduction half: (chromium was reduced)
14H⁺+Cr₂O₇²⁻+6e⁻→2Cr³⁺+7H₂O

H⁺ comes from the solution.  It is in the final reaction since in redox reactions the oxygen is turned into water since it can't just go away.  I multiplied the oxidation half reaction by 3 in order for both half reactions to half the same number of electrons since equal numbers of electrons need to be lost and gained for the reaction to be balanced.

I hope this helps.  Let me know if anything is unclear.
8 0
3 years ago
If 1.6 moles of an ideal gas are at a temperature of 25c and a pressure of 0.91 atm hg, what volume would the gas occupy, in lit
Fiesta28 [93]
From\ Ideal\ Gas\ Law:\\\\PV=nRT\\\\
P-pressure\\V-volume\\n-number\ of\ moles\\R- universal\ gas\ constant\\T-absolute\ tmeperature\\\\
R=\ 8,3145J/ mol\ K\\P=0,91atm\\
n=1,6moles\\T=25c\\\\
Converting\ units:\\\\
1atm=101,3kPa=101,3*10^3\\
0,91atm=0,91*101,3*10^3=92,183*10^3Pa\\T=25c=273+25=298K\\\\
V=\frac{nRT}{P}=\frac{1,6*8,3145*298}{92183}=0,043m^3=43liters\\\\Answer\ is\ 43\ liters.
8 0
3 years ago
Write the electron configuration for the electrons identified by the following quantum numbers:
vesna_86 [32]

Answer:

see the answer at the pic

3 0
3 years ago
When molten rock undergoes crystallization above ground, what type of rock results?
vodka [1.7K]
I am pretty sure that the answer is B. extrusive rock. I hope that this helps you!! Good Luck!!
5 0
3 years ago
Read 2 more answers
What is the mass of 1.7 × 1023 atoms of zinc (Zn)?
Rudiy27

Number of moles is defined as the ratio of given mass in g to the molar mass.

The mathematical formula is:

Number of moles = \frac{given mass in g}{molar mass}   (1)

Number of zinc atoms is equal to 1.7\times10^{23}, by Avogadro number, number of moles can be calculated.

As, 1 mol=6.022\times10^{23} atoms, hence,

1.7\times10^{23}\times\frac{1 mol}{6.022\times10^{23} }

= 0.2822 mol

Now, from formula (1), calculate mass in g (molar mass of zinc = 65.4 g/mol)

0.2822 mol = \frac{mass in g}{65.4 g/mol}

mass in g  = {0.2822 mol \times 65.4 g/mol

= 18.45588 g

Thus, by rounding off the above number, it will come near about 19 g approximately.

Hence, option (C) is the correct answer.



 



8 0
3 years ago
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