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Lena [83]
3 years ago
11

The rate at which energy is transferred is called a power b kinetic energy c work d time

Chemistry
2 answers:
grandymaker [24]3 years ago
8 0
This is one of the definitions that is used to define C. Work. It is a change in energies from one form to another within some time frame.
eduard3 years ago
6 0

I pretty sure its C. Work

If wrong lemme know

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The change of phase from a vapor to a liquid is called _____. evaporation condensation distillation vaporization
anastassius [24]
Its condensation

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2 years ago
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4. Calculate the relative molecular masses of the following substances [RAM: H=1, O=16, S=32, C=12, N=14] a. CH2(NH2)COOH b. H2S
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a. CH2(NH2)COOH

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4 0
2 years ago
Which ion is a polyatomic ion?<br><br> NH4+<br> Cl−<br> Ca2+<br> F−
torisob [31]

Answer:

Water, 35 liters. Carbon, 20 kilograms. Ammonia, 4 liters. Lime, 1.5 kilograms. Phosphorous, 800 grams. Salt, 250 grams. Saltpeter, 100 grams. Sulfur, 80 grams. Fluorine, seven-point-five. Iron, five. Silicon, three grams. And trace

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the ingredients of the average adult,right down to the last specks of protein in your eyelashes. And even though science has given us the entire physical breakdown, there's never been a successful attempt at bringing a human to life. There's still something missing. Something scientists haven't been able to find in centuries of research. ...and in case you're wondering, all those ingredients can be bought on a child's allowance. humans can be made rather cheap. There's no magic to it.

4 0
2 years ago
Give the percent yield when 28.16 g of CO2 are formed from the reaction of 8.000 moles of C8H18 with 16.00 moles of O2.
kipiarov [429]

Answer:

Percent yield of CO₂ is 6.25 %.

Explanation:

Given data:

Percent yield of CO₂ = ?

Actual yield of CO₂ = 28.16 g

Number of moles of C₈H₁₈ = 8.000 mol

Number of moles of O₂ = 16.00 mol

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂  →  16CO₂ + 18H₂O

Now we will compare the moles of C₈H₁₈ and O₂  with CO₂.

                 C₈H₁₈            :          CO₂

                    2                :             16

                  8.000          :            16/2×8.000 = 64 mol

                   O₂               :             CO₂

                    25              :              16

                     16              :              16/25×16= 10.24 mol

Less number of moles  of CO₂ are produced from 16 moles of O₂. it will limit the yield of CO₂.

Grams of CO₂ produced:

Mass = number of moles × molar mass

Mass = 10.24 mol  × 44 g/mol

Mass = 450.56 g

Percentage yield of CO₂:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 28.16 g/ 450.56 g× 100

Percentage yield = 6.25 %

               

   

7 0
2 years ago
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