All categories

3 years ago

8. Balance the following nuclear equations: ^65/30Ca -> ^65/29Sc +_______

Chemistry

1 answer:

a_sh-v [17]3 years ago

3 0

Explanation:

⁶⁵₃₀Ca → ⁶⁵₂₉Sc + ⁿₓH

The reaction above is nuclear reaction.

In a nuclear reaction, the mass number and atomic number must be conserved.

The mass number is the superscript before the atom

Atomic number is the subscript before the atom

Conserving mass number:

65 = 65 + n

n = 0

conserving atomic number:

30 = 29 + x

x = 1

The unknown atom is a positron i.e a positively charged electron: ⁰₁e

⁶⁵₃₀Ca → ⁶⁵₂₉Sc + ⁰₁e

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

You might be interested in

A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui

deff fn [24]

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

$Volume(V)=\frac{Mass(m)}{Density (\rho)}$

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force = $\rho\times gV$

Where

$\rho$ is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

$mg=\rho\times gV+T$

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

$6.1\times 9.81=\rho\times 9.81\times 0.002346+26$

$33.841=\rho\times 9.81\times 0.002346$

$\rho=\frac{33.841}{9.81\times 0.002346}$

$\rho=1470.43 kgm^3$

<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

6 0

4 years ago

Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el

LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>

8 0

3 years ago

How many moles is in 2.52*10^24 molecules of water?

nataly862011 [7]

Hi friend
--------------
Your answer
-------------------

Water = H2O

Number of molecules in one mole of water = 6.022 × 10²³ [Avogadro's constant]

Given number of molecules = 2.52 × 10²³

So,
------

Number of moles =
$\frac{2.52 \times 10 {}^{24} }{6.022 \times 10 {}^{23} } \\ \\ = 4.184 \: (approximately)$

HOPE IT HELPS

3 0

3 years ago

A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is

IRINA_888 [86]

Answer:

no. of water molecules associated to each molecule of $MnCl_2$ = 4